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!! Maths HL Paper 2 2016 - Before and After

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  • Closed Accounts Posts: 855 ✭✭✭TSMGUY


    angleBCD is 66 degrees for me. Does that ring any bells?

    I got 59 degrees but I didn't know what the f*** I was doing.


  • Registered Users Posts: 39 InTheNight


    angleBCD is 66 degrees for me. Does that ring any bells?

    Think I got 65..


  • Registered Users Posts: 626 ✭✭✭Seaaan


    Q4A part 2 anyone? Did you get y equals root x?

    I left it it as y^2 = x, only noticed when looking through my English copy after.. -1 :(

    Also circle (x-7)^2 +(y-6)^2 = 25?


  • Registered Users Posts: 182 ✭✭DownOneTourist


    anyone get 15.something metres squared for the area of the sides of the 4 sided pyramid?


  • Registered Users Posts: 626 ✭✭✭Seaaan


    bookworm20 wrote: »
    q5a ii) anyone rember their answers, it was the one about the arrows and finding the probability that they will win

    Something around .1 is what I got, I got probability of each possible way to win and added them


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  • Registered Users Posts: 570 ✭✭✭Jane98


    TSMGUY wrote: »
    I thought they were making a profit at the start??? Because you have to times the 2500/2600 by zero as they don't pay anything out if you lose. Am I wrong? Chit....

    to get the expect payout: 1000x1/2600 +50x9/2600+50x9/2600+50x81/2600 +0x2500/2600 = 2.29 so we have an expected loss of 29c if they charge €2


  • Closed Accounts Posts: 140 ✭✭luftmensch


    angleBCD is 66 degrees for me. Does that ring any bells?

    66 sounds familiar. Not sure though.


  • Registered Users Posts: 570 ✭✭✭Jane98


    Seaaan wrote: »
    Something around .1 is what I got, I got probability of each possible way to win and added them

    i got 13/120 whic is approx. 01


  • Registered Users Posts: 38 bookworm20


    To avoid debate here are some answers that im pretty sure are right but feel free to disagree:

    orthrocentre: (7,6)
    circle s: two solutins for centre one of them is 5,6 or 6,5 cant really remeber :)
    triangle in semi cirlce: y=root x
    venn diagram: x=0.15
    angle |∠BCD| in roof lantern: 65
    area of roof lantern: 15
    Reason why The research institute took many large random samples of farm size: because the means would be normally distributed (i think ;)
    the value of n in last question: 494

    Again feel free to disagree :)


  • Registered Users Posts: 39 InTheNight


    Did anyone's answers for the circle have decimals? 7.xx and 11.xx?


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  • Registered Users Posts: 38 bookworm20


    Jane98 wrote: »
    i got 13/120 whic is approx. 01

    Yea I got that too


  • Registered Users Posts: 626 ✭✭✭Seaaan


    bookworm20 wrote: »
    q5a ii) anyone rember their answers, it was the one about the arrows and finding the probability that they will win

    Something around .1 is what I got, I got probability of each possible way to win and added them


  • Registered Users Posts: 626 ✭✭✭Seaaan


    Jane98 wrote: »
    i got 13/120 whic is approx. 01

    Yeh I had that and wrote decimal too


  • Closed Accounts Posts: 2,823 ✭✭✭DublinArnie


    Ahhhh ****, realised I made a stupid mistake with the lantern area by halving the Base length :(.


  • Registered Users Posts: 182 ✭✭DownOneTourist


    Ahhhh ****, realised I made a stupid mistake with the lantern area by halving the Base length :(.

    thats right though. 2(1/2B(H))+2(1/2B(H)) theres 2 of each type of triangle


  • Registered Users Posts: 570 ✭✭✭Jane98


    InTheNight wrote: »
    Did anyone's answers for the circle have decimals? 7.xx and 11.xx?

    yeah i got 7 and 7.****something


  • Registered Users Posts: 570 ✭✭✭Jane98


    bookworm20 wrote: »
    To avoid debate here are some answers that im pretty sure are right but feel free to disagree:

    orthrocentre: (7,6)
    circle s: two solutins for centre one of them is 5,6 or 6,5 cant really remeber :)
    triangle in semi cirlce: y=root x
    venn diagram: x=0.15
    angle |∠BCD| in roof lantern: 65
    area of roof lantern: 15
    Reason why The research institute took many large random samples of farm size: because the means would be normally distributed (i think ;)
    the value of n in last question: 494

    Again feel free to disagree :)

    how did u get centre of the circle?


  • Registered Users Posts: 182 ✭✭DownOneTourist


    i just tried to tot up my scores giving 4/10 attempt marks where i made a good attempt and over both papers i wound up with 89.5 percent. Really annoying! I wont have peace of mind until august. What if I gave myself too much? What if gave myself too little? Oh the feels!


  • Registered Users Posts: 570 ✭✭✭Jane98


    Papers up now!


  • Registered Users Posts: 107 ✭✭malnurtured


    thats right though. 2(1/2B(H))+2(1/2B(H)) theres 2 of each type of triangle

    2 types of triangle? What?

    I just did 4 x (1/2BxH) ...?


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  • Closed Accounts Posts: 216 ✭✭BrownTrout


    Seaaan wrote:
    Also circle (x-7)^2 +(y-6)^2 = 25?


    Yup


  • Closed Accounts Posts: 2,823 ✭✭✭DublinArnie


    2 types of triangle? What?

    I just did 4 x (1/2BxH) ...?

    That's what I did but I recall getting 8m squared.

    The question asked for the four triangles, maybe those who got 15 etc added the bottom aswell?


  • Registered Users Posts: 38 bookworm20


    did anyone get the value of n in last question to be 494


  • Registered Users Posts: 182 ✭✭DownOneTourist


    2 types of triangle? What?

    I just did 4 x (1/2BxH) ...?

    one triangle had base 3, the other had base 2.5, at least for me


  • Registered Users Posts: 107 ✭✭malnurtured


    one triangle had base 3, the other had base 2.5, at least for me

    God damn it. Yeah, that makes sense. Idiotic stuff on my part.


  • Registered Users Posts: 38 bookworm20


    Jane98 wrote: »
    how did u get centre of the circle?

    It was simultaneous equations. Make the distance from the centre to the tangent equal to 5(the radius). Then sub in the equation of the line XC keeping in mind the absolute value brackets and u will get two values for x and two values for y (where x=-g and y=-f). Hope that helps ;)


  • Closed Accounts Posts: 2,823 ✭✭✭DublinArnie


    bookworm20 wrote: »
    It was simultaneous equations. Make the distance from the centre to the tangent equal to 5(the radius). Then sub in the equation of the line XC keeping in mind the absolute value brackets and u will get two values for x and two values for y (where x=-g and y=-f). Hope that helps ;)

    Wtf, I did all of that but instead of keeping absolute values, I squared both sides and then proceeded to do messy algebra.

    So close....


  • Registered Users Posts: 570 ✭✭✭Jane98


    The centres are (6,7) and (-8,5)


  • Registered Users Posts: 38 bookworm20


    bookworm20 wrote: »
    did anyone get the value of n in last question to be 494

    bump


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  • Registered Users Posts: 29 randomlad727


    bookworm20 wrote: »
    bump

    Yes I think I got that

    Were we not supposed to get just one equation of the circle? I got one equation and could of got the second but I didn't bother


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