!! Maths HL Paper 2 2016 - Before and After

DownOneTourist wrote: »

Q4A part 2 anyone? Did you get y equals root x?

I left it it as y^2 = x, only noticed when looking through my English copy after.. -1

Also circle (x-7)^2 +(y-6)^2 = 25?

anyone get 15.something metres squared for the area of the sides of the 4 sided pyramid?

bookworm20 wrote: »

q5a ii) anyone rember their answers, it was the one about the arrows and finding the probability that they will win

Something around .1 is what I got, I got probability of each possible way to win and added them

TSMGUY wrote: »

I thought they were making a profit at the start??? Because you have to times the 2500/2600 by zero as they don't pay anything out if you lose. Am I wrong? Chit....

to get the expect payout: 1000x1/2600 +50x9/2600+50x9/2600+50x81/2600 +0x2500/2600 = 2.29 so we have an expected loss of 29c if they charge €2

luftmensch

DownOneTourist wrote: »

angleBCD is 66 degrees for me. Does that ring any bells?

66 sounds familiar. Not sure though.

Seaaan wrote: »

Something around .1 is what I got, I got probability of each possible way to win and added them

i got 13/120 whic is approx. 01

To avoid debate here are some answers that im pretty sure are right but feel free to disagree:

orthrocentre: (7,6)
circle s: two solutins for centre one of them is 5,6 or 6,5 cant really remeber

triangle in semi cirlce: y=root x
venn diagram: x=0.15
angle |∠BCD| in roof lantern: 65
area of roof lantern: 15
Reason why The research institute took many large random samples of farm size: because the means would be normally distributed (i think

the value of n in last question: 494

Again feel free to disagree

InTheNight

Did anyone's answers for the circle have decimals? 7.xx and 11.xx?

Jane98 wrote: »

i got 13/120 whic is approx. 01

Yea I got that too

bookworm20 wrote: »

q5a ii) anyone rember their answers, it was the one about the arrows and finding the probability that they will win

Something around .1 is what I got, I got probability of each possible way to win and added them

Jane98 wrote: »

i got 13/120 whic is approx. 01

Yeh I had that and wrote decimal too

DublinArnie

Ahhhh ****, realised I made a stupid mistake with the lantern area by halving the Base length

DublinArnie wrote: »

Ahhhh ****, realised I made a stupid mistake with the lantern area by halving the Base length .

thats right though. 2(1/2B(H))+2(1/2B(H)) theres 2 of each type of triangle

InTheNight wrote: »

Did anyone's answers for the circle have decimals? 7.xx and 11.xx?

yeah i got 7 and 7.****something

bookworm20 wrote: »

To avoid debate here are some answers that im pretty sure are right but feel free to disagree:

orthrocentre: (7,6)
circle s: two solutins for centre one of them is 5,6 or 6,5 cant really remeber
triangle in semi cirlce: y=root x
venn diagram: x=0.15
angle |∠BCD| in roof lantern: 65
area of roof lantern: 15
Reason why The research institute took many large random samples of farm size: because the means would be normally distributed (i think
the value of n in last question: 494

Again feel free to disagree

how did u get centre of the circle?

i just tried to tot up my scores giving 4/10 attempt marks where i made a good attempt and over both papers i wound up with 89.5 percent. Really annoying! I wont have peace of mind until august. What if I gave myself too much? What if gave myself too little? Oh the feels!

Papers up now!

malnurtured

DownOneTourist wrote: »

thats right though. 2(1/2B(H))+2(1/2B(H)) theres 2 of each type of triangle

2 types of triangle? What?

I just did 4 x (1/2BxH) ...?

BrownTrout

Seaaan wrote:

Also circle (x-7)^2 +(y-6)^2 = 25?

Yup

DublinArnie

malnurtured wrote: »

2 types of triangle? What?

I just did 4 x (1/2BxH) ...?

That's what I did but I recall getting 8m squared.

The question asked for the four triangles, maybe those who got 15 etc added the bottom aswell?

did anyone get the value of n in last question to be 494

malnurtured wrote: »

2 types of triangle? What?

I just did 4 x (1/2BxH) ...?

one triangle had base 3, the other had base 2.5, at least for me

malnurtured

DownOneTourist wrote: »

one triangle had base 3, the other had base 2.5, at least for me

God damn it. Yeah, that makes sense. Idiotic stuff on my part.

Jane98 wrote: »

how did u get centre of the circle?

It was simultaneous equations. Make the distance from the centre to the tangent equal to 5(the radius). Then sub in the equation of the line XC keeping in mind the absolute value brackets and u will get two values for x and two values for y (where x=-g and y=-f). Hope that helps

DublinArnie

bookworm20 wrote: »

It was simultaneous equations. Make the distance from the centre to the tangent equal to 5(the radius). Then sub in the equation of the line XC keeping in mind the absolute value brackets and u will get two values for x and two values for y (where x=-g and y=-f). Hope that helps

Wtf, I did all of that but instead of keeping absolute values, I squared both sides and then proceeded to do messy algebra.

So close....

The centres are (6,7) and (-8,5)