***JC 2014 Maths Paper One - Fri. June 6th 2014 - all levels***

nokia211

ComputerKing wrote: »

Well a question like it came up in our pre and I did it like you and I only got high partial and when I asked my teacher whos a JC corrector she said in the JC I'd get low partial for doing it the way I did.

I just hope that they will accept it because if we weren't given the table or we would be able to do it

DanielChester

Liordi wrote: »

Don't think you can solve part five with this, though.
Also, your formula doesn't hold through.

S = 20
C = 33
33 =/= 20 + 23

You dont give a value for C , as C is the output, lol..

Liordi

If I want to get 20 sterling then.

20 + 23 = 43.
43 is incorrect from the table.

DanielChester

Liordi wrote: »

If I want to get 20 sterling then.

20 + 23 = 43.
43 is incorrect from the table.

thats because of the standing charge, i already stated it in my formula in the exam

ComputerKing

nokia211 wrote: »

I just hope that they will accept it because if we weren't given the table or we would be able to do it

Well you'll probably get low or maybe high partial if your lucky. But from what my teacher said from one of here in services was the point of the question was to check your ability to apply the equation of the line formula from your co ordinate geometry of the line. This is something they are going to do in project maths as well is link all the different stands and topics no matter what paper.

Liordi

DanielChester wrote: »

thats because of the standing charge, i already stated it in my formula in the exam

So, how does your formula work?

ComputerKing

DanielChester wrote: »

thats because of the standing charge, i already stated it in my formula in the exam

I'm sorry I can't see how your formula works just post exactly what the formula you wrote down for John was and exactly what each letter you used like x or y means.

DanielChester

Liordi wrote: »

So, how does your formula work?

lets say i want £50.
50+23 = 73 euro simple

Liordi

DanielChester wrote: »

lets say i want £50.
50+23 = 73 euro simple

Not the same answer as the correct formula.

DanielChester

Liordi wrote: »

Not the same answer as the correct formula.

There is no "correct" formula. lol

Liordi

DanielChester wrote: »

There is no "correct" formula. lol

1.15x + 10 = y
Where x = sterling
y = euro

DanielChester

Liordi wrote: »

1.15x + 10 = y
Where x = sterling
y = euro

Congratulations your formula works but it isn't the "correct" formula, its just a correct answer as it works, as long as the formula does what the question tells you to do it does not matter wether or not it looks completely different to yours.

Liordi

DanielChester wrote: »

Congratulations your formula works but it isn't the "correct" formula, its just a correct answer as it works, as long as the formula does what the question tells you to do it does not matter wether or not it looks completely different to yours.

That isn't my formula, I got the question wrong.
I'm just saying your formula doesn't work.

DanielChester

Liordi wrote: »

That isn't my formula, I got the question wrong.
I'm just saying your formula doesn't work.

I'm pretty sure it does work my dear friend

MangoMachine

Liordi wrote: »

Ah, that's pretty neat.
I'd imagine you'd get marks for it, but I presume you didn't solve part (v)?

I used y=mx+b for both question (iii) and (iv) where m is the slope and b is where the line hits the y-axis. For part (v), I let equation (iii)=(iv) and it equaled 200. I verified it, and it looked correct.

VG31

There are different formulae and letters you can use. I had 1.15n + 10 and 1.2n for the other one (n being the amount in £).

ComputerKing

DanielChester wrote: »

Congratulations your formula works but it isn't the "correct" formula, its just a correct answer as it works, as long as the formula does what the question tells you to do it does not matter wether or not it looks completely different to yours.

That was the correct formula it also would have accepted the slope as a fraction. It's what they were looking for and is what teachers were told the sec wanted at in services

S_Hick12

DanielChester wrote: »

I'm pretty sure it does work my dear friend

Sorry to tell ya, but it really doesn't.

ComputerKing

VG31 wrote: »

There are different formulae and letters you can use. I had 1.15n + 10 and 1.2n for the other one (n being the amount in £).

You can use what ever letters you wanted but basically what they were looking for was it in the form of y=mx +c they don't care what letters you use once it's in that form.

DanielChester

ComputerKing wrote: »

You can use what ever letters you wanted but basically what they were looking for was it in the form of y=mx +c they don't care what letters you use once it's in that form.

oh, ohwell at least i'll get some marks, not like the question carried that many to knock me down a grade.

Kelly090

ComputerKing wrote: »

That was the correct formula it also would have accepted the slope as a fraction. It's what they were looking for and is what teachers were told the sec wanted at in services

so would they accept :
10+23/20n Jake
and 24/20n for Susan?

Liordi

Kelly090 wrote: »

so would they accept :
10+23/20n Jake
and 24/20n for Susan?

10 + 20/23x
20/24x

Kelly090

Liordi wrote: »

10 + 20/23x
20/24x

So yes??

bidonville2

For Jack I did: Tn = 23n +10, where "Tn" is the amount in sterling with every £20 increase raising the value of Tn by 1, ie. at £20, Tn = 1 and at £60, Tn = 3. "n" represents the cost in €.
For Sarah I did: Tn = 24n, with the same explanation.
My formulae work but would I get the marks for it?

ComputerKing

Kelly090 wrote: »

so would they accept :
10+23/20n Jake
and 24/20n for Susan?

Yes the letter doesn't matter don't you remember that from algebra you could have had r or f for all they care but they were looking for that y=mx+c or in the format of y=mx+c

ComputerKing

Did no ones teachers go through what happened on in services with them?

Kelly090

ComputerKing wrote: »

Yes the letter doesn't matter don't you remember that from algebra you could have had r or f for all they care but they were looking for that y=mx+c or in the format of y=mx+c

Thanks, just out of curiosity how would u solve that?

Liordi

Kelly090 wrote: »

Thanks, just out of curiosity how would u solve that?

y = 1.15x + 10 (-) => -y = -1.15x - 10
y = 1.2x

.05x - 10 = 0
.05x = 10 (20)
x = 200

ComputerKing

Kelly090 wrote: »

Thanks, just out of curiosity how would u solve that?

So you let y= to the cost in euro
Let m as always =to slope so let's say 23/20
Then let x= the amount in sterling
And c as all ways = y intercept so in this case 10

Therefore y= 23/20(x) +10

yaEHya

What did peoples thing look like for when they had to draw how fast the cone would fill up?