***JC 2014 Maths Paper One - Fri. June 6th 2014 - all levels***

Liordi

Kelly090 wrote: »

Can anyone please remember the range of values for the last parts in question fourteen (functions) please?

I'd have to draw the graph out again to check what they were.
Might do it later if I get a chance.

Ferrotype

Fifii wrote: »

Why did they let y= -3.3333333?!
For the Ball Question I said that it would land
after 4 seconds because the pattern was exponential or could form a parabola and that at 2 seconds it was at the highest point of the parabola so it would take the same time to land:(
Also for the n^2+n-41 I said that the plus and minus would cancel each other out leaving just the 41^2 which is obviously a composite number as it can be divided by 41:D
Can someone show me how I should have answered the last 2 parts of the last q ie the ranges?

You just had to look at the graph and see for example for g(x) is greater than or equal to zero by determining the point where the graph crossed the x axis and and the the answer was x is equal to or greater than that number.
I said the same as you for the ball question and i seemed to be the only one who got it in my centre. so

Emmie123

Kelly090 wrote: »

Can anyone please remember the range of values for the last parts in question fourteen (functions) please?

If I'm thinking of the right question, I (and people I know) got around -1.5 to 2

Fifii

Ferrotype wrote: »

You just had to look at the graph and see for example for g(x) is greater than or equal to zero by determining the point where the graph crossed the x axis and and the the answer was x is equal to or greater than that number.
I said the same as you for the ball question and i seemed to be the only one who got it in my centre. so

Thanks! I hope thats a good thing that we did it the same way:) Another thing that threw me a bit was the perimeter question I think I got something like 2 square root of 10:(

nokia211

Can someone please clarify wether or not you had to do the two graphs on the same graph for question 14 and would my formula works for question 9 For question 9

I think I got a different equation for jack I got 10+ 7.6666666666666 = y
It still worked thought when I put in what x was
Do ya think they will accept different equations as long as they work?
For Susan it was 0 + 6x = y
This also worked but I think these equations are different from everyone else's
Where x is the difference between sterling and euro - 10
i don't think i got the simultaneous right though

Msrebeckyxo

I said the ball was up in the air for 7.5 seconds, was this wrong? 😂

Liordi

Msrebeckyxo wrote: »

I said the ball was up in the air for 7.5 seconds, was this wrong? 😂

I got 7.4s, but it said approximately so hopefully we'll both be fine.

Liordi

nokia211 wrote: »

Can someone please clarify wether or not you had to do the two graphs on the same graph for question 14

I think I got a different equation for jack I got 10+ 7.6666666666666 = y
For Susan it was 0 + 6x = y
This also worked but I think these equations are different from everyone else's
Where x is the difference between sterling and euro - 10

Is 7.666.. your x value for Jackie?
Also, it doesn't matter if you drew the functions on the same graph or not.

nokia211

Liordi wrote: »

Is 7.666.. your x value for Jackie?
Also, it doesn't matter if you drew the functions on the same graph or not.

am my equation was 10+7.666666666x=y
where x is the difference between euro and sterling - 10
eg
10 +7.666666666 X3 = 33
i got three by getting the difference and subtracting 10
it does work but its different from everyones else's answer

MissCupcake

nokia211 wrote: »

am my equation was 10+7.666666666x=y
where x is the difference between euro and sterling - 10
eg
10 +7.666666666 X3 = 33
i got three by getting the difference and subtracting 10
it does work but its different from everyones else's answer

which graph was f(x) and which was g(x)

Liordi

MissCupcake wrote: »

which graph was f(x) and which was g(x)

It's for question 9 not the functions.

nokia211

MissCupcake wrote: »

which graph was f(x) and which was g(x)

it said on the same axes and scales so i put both of them as in fx the quadratic and gx the line of the same graph

Liordi

nokia211 wrote: »

am my equation was 10+7.666666666x=y
where x is the difference between euro and sterling - 10
eg
10 +7.666666666 X3 = 33
i got three by getting the difference and subtracting 10
it does work but its different from everyones else's answer

Does it work for any values other than 33?

ComputerKing

nokia211 wrote: »

am my equation was 10+7.666666666x=y
where x is the difference between euro and sterling - 10
eg
10 +7.666666666 X3 = 33
i got three by getting the difference and subtracting 10
it does work but its different from everyones else's answer

Don't fully understand what your saying but I think its wrong they were looking for so that you subbed I'm the sterling amount as x or what ever and it gave you the euro as you don't have the euro value. So you can't can have them putting in the difference between the two values.

nokia211

Liordi wrote: »

Does it work for any values other than 33?

yes it works for all the values

Liordi

nokia211 wrote: »

yes it works for all the values

but why're you multiplying by 3?
The difference is 13?

nokia211

ComputerKing wrote: »

Don't fully understand what your saying but I think its wrong they were looking for so that you subbed I'm the sterling amount as x or what ever and it gave you the euro as you don't have the euro value. So you can't can have them putting in the difference between the two values.

did it not ask write down a formula to respect what he would get in euro which is what i have done

nokia211

Liordi wrote: »

but why're you multiplying by 3?
The difference is 13?

yeah put as i said you take away 10

Liordi

nokia211 wrote: »

yeah put as i said you take away 10

So you're doing..33-20-10 x 7.66 + 10?

nokia211

Liordi wrote: »

So you're doing..33-20-10 x 7.66 + 10?

yes

ComputerKing

nokia211 wrote: »

did it not ask write down a formula to respect what he would get in euro which is what i have done

Yes but I'm assuming they what the formula to calculate this with out already haveing the amount in euro which it seems like yours does.

Liordi

nokia211 wrote: »

yes

How does it work for when €56 and £40?

56-40-10 x 7.66666 + 10...?

nokia211

ComputerKing wrote: »

Yes but I'm assuming they what the formula to calculate this with out already haveing the amount in euro which it seems like yours does.

yes maybe but they didn't specify this
do ya think i would still get makes though
As it does work

nokia211

Liordi wrote: »

How does it work for when €56 and £40?

56-40-10 x 7.66666 + 10...?

6 x 7.666666666666 + 10
the difference is 16 -10 = 6

DanielChester

Why should complicated formulas? Mine was C = S + 23 for Jack and C = S + 24 for Sarah..
--
C = Cost it would make in euros
S = Amount of sterling you want


???

Liordi

Ah, that's pretty neat.
I'd imagine you'd get marks for it, but I presume you didn't solve part (v)?

DanielChester

Why such complicated formulas? Mine was C = S + 23 for Jack and C = S + 24 for Sarah..
--
C = Cost it would make in euros
S = Amount of sterling you want


???

ComputerKing

nokia211 wrote: »

yes maybe but they didn't specify this
do ya think i would still get makes though
As it does work

Well a question like it came up in our pre and I did it like you and I only got high partial and when I asked my teacher whos a JC corrector she said in the JC I'd get low partial for doing it the way I did.

nokia211

Liordi wrote: »

Ah, that's pretty neat.
I'd imagine you'd get marks for it, but I presume you didn't solve part (v)?

i don't know i got two answers for x and y wasn't really sure what to do with them

Liordi

DanielChester wrote: »

Why such complicated formulas? Mine was C = S + 23 for Jack and C = S + 24 for Sarah..
--
C = Cost it would make in euros
S = Amount of sterling you want


???

Don't think you can solve part five with this, though.
Also, your formula doesn't hold through.

S = 20
C = 33
33 =/= 20 + 23