LC Off Topic Thread (2015/16)

coolerboy · 05-10-2014 04:36PM

Take Your Pants Off wrote: »

Hi, lads any help in this question.
Solve 2x^2 - root3x -3=0
I think you have to sub in a substitution such as u.for root3x

Can u take a picture of the question instead its kind of hard to start without the wording

Consonata wrote: »

Do they really matter enough to you that much that it is worth appealing them? Surely its better to be looking to your future exams than reminiscing on past ones.

Yeah well because I meant to be getting 350 for a ps4 for getting 6As so I need them so bad

... but unfortunately the appeal dates has gone thanks beca19 for informing me!!!

DublinArnie · 05-10-2014 04:38PM

Take Your Pants Off wrote: »

Hi, lads any help in this question.
Solve 2x^2 - root3x -3=0
I think you have to sub in a substitution such as u.for root3x

Take a pic like coolboy said.

coolerboy · 05-10-2014 04:40PM

DublinArnie wrote: »

Take a pic like coolboy said.

Haha I really need to change my name

its really cheesy

DublinArnie · 05-10-2014 04:45PM

I think this is it.

Take Your Pants Off · 05-10-2014 05:07PM

DublinArnie wrote: »

I think this is it.

But shouldnt square root 3 b - in ur formula as it says in the qs.

DublinArnie · 05-10-2014 05:08PM

Take Your Pants Off wrote: »

But shouldnt square root 3 b - in ur formula as it says in the qs.

Convert the X answers into decimals then.

Take a picture of the question.

Take Your Pants Off · 05-10-2014 05:13PM

DublinArnie wrote: »

Convert the X answers into decimals then.

Take a picture of the question.

Ah I see its just that when 2 minus turn to plus. Which you already done beforehand.
Thanks mate always a help.

AlanS181824 · 05-10-2014 06:16PM

DublinArnie wrote: »

I think this is it.

That's the most confusing shîte ever! Haha!

DublinArnie · 05-10-2014 06:54PM

AlanS181824 wrote: »

That's the most confusing shîte ever! Haha!

It's the '-b' formula, and you just pluck the numbers into it. If a quadratic equation (ax^2 + bx + c) ever has a root in it, then you do the '-b' formula to get your two X values.

It's very easy. :pac:

coolerboy · 05-10-2014 07:06PM

DublinArnie wrote: »

It's the '-b' formula, and you just pluck the numbers into it. If a quadratic equation (ax^2 + bx + c) ever has a root in it, then you do the '-b' formula to get your two X values.

It's very easy. :pac:

What did you get in maths in your jc you seem really good at it

DublinArnie · 05-10-2014 07:29PM

coolerboy wrote: »

What did you get in maths in your jc you seem really good at it

Actually got a B and got a D on my mocks. Between the JC and Mock period, I done every past-paper and sample paper like three times (they all got corrected).

coolerboy · 05-10-2014 08:54PM

DublinArnie wrote: »

Actually got a B and got a D on my mocks. Between the JC and Mock period, I done every past-paper and sample paper like three times (they all got corrected).

Ill say you were just touching the A.
Haha I got a B (70%)in the mocks which was the highest in my class and year of 130!!! and got a B in the junior Ill say I got bout 85 86 and was brought down to a B as the A rate was down this year.

DublinArnie wrote: »

Actually got a B and got a D on my mocks. Between the JC and Mock period, I done every past-paper and sample paper like three times (they all got corrected).

Same I did two pairs of exam papers!!!

iCrazzy · 05-10-2014 09:44PM

Hey lads. I see there is lots of people here out helping each other. So I thought maybe someone could help me with a question I was stuck on.
I was out on Thursday when the teacher explained it so I could not get any chance.
It is Q5 C
Now I tried the example on the previous page and it told me to substitute the u for y+4overy and I ended with a quadratic that worked out as u= 5 and 1 but from there on I have no clue.

coolerboy · 05-10-2014 09:46PM

iCrazzy wrote: »

Hey lads. I see there is lots of people here out helping each other. So I thought maybe someone could help me with a question I was stuck on.
I was out on Thursday when the teacher explained it so I could not get any chance.
It is Q5 C
Now I tried the example on the previous page and it told me to substitute the u for y+4overy and I ended with a quadratic that worked out as u= 5 and 1 but from there on I have no clue.

What do you have to find. Solve or simplify

iCrazzy · 05-10-2014 09:48PM

coolerboy wrote: »

What do you have to find. Solve or simplify

Solve.

DublinArnie · 05-10-2014 09:53PM

On it now.

coolerboy · 05-10-2014 09:57PM

iCrazzy wrote: »

Solve.

Coming

iCrazzy wrote: »

Solve.

I have to admit it's a tricky one but im near the answer

DublinArnie · 05-10-2014 10:07PM

coolerboy wrote: »

I have to admit it's a tricky one but im near the answer

I have an annoying 16/y which I can't get of :mad:

iCrazzy · 05-10-2014 10:18PM

Thanks lads.
But if you cant get it just leave it.
I dont want ye to be wasting your time after doing me a qs.
Ill see if I can get a friend to help me tomorrow.

DublinArnie · 05-10-2014 10:20PM

My attempt, I probably got it wrong.

y = 1 OR y = - 20/27

Got a friend to it aswell and she got the same answer. My brain is absolutely melted now.

iCrazzy · 05-10-2014 10:36PM

DublinArnie wrote: »

Got a friend to it aswell and she got the same answer. My brain is absolutely melted now.

There are 3 answers at the back of the book.
1 2 and 4 ??!!
But thank you soo much for taking ur time out especially on a sunday I know how busy everyone prep for school etc.

DublinArnie · 05-10-2014 10:38PM

iCrazzy wrote: »

There are 3 answers at the back of the book.
1 2 and 4 ??!!
But thank you soo much for taking ur time out especially on a sunday I know how busy everyone prep for school etc.

Three answers for a quadratic question? That's a first.

No problem.

phoebo · 05-10-2014 10:41PM

iCrazzy wrote: »

There are 3 answers at the back of the book.
1 2 and 4 ??!!
But thank you soo much for taking ur time out especially on a sunday I know how busy everyone prep for school etc.

I did it and got 1,2 and 4 as answers! Can post a picture if needed

DublinArnie · 05-10-2014 10:44PM

phoebo wrote: »

I did it and got 1,2 and 4 as answers! Can post a picture if needed

Would love a picture please.

phoebo · 05-10-2014 10:46PM

DublinArnie wrote: »

Would love a picture please.

Just saw that since i am a new user I can't post pictures but if you give me a minute I'll type it out! :-)

coolerboy · 05-10-2014 10:52PM

phoebo wrote: »

Just saw that since i am a new user I can't post pictures but if you give me a minute I'll type it out! :-)

Use the attachment

phoebo · 05-10-2014 10:56PM

Answer:

let y+4/y = m

m^2 -9m +20=0
(m-5)(m-4)
m-5=0
m=5

m-4=0
m=4

y+4/y=5

y^2 +4=5y (i multiplied across by y to remove the fraction)
y^2 -5y + 4=0

(y-4)(y-1)
y-4=0
*y=4*

y-1=0
*y=1*

y+4/y=4
y^2 +4= 4/y
y^2 -4y +4=0
(y-2)(y-2)
y-2=0
*y=2*

Hope that helps!

DublinArnie · 05-10-2014 11:03PM

phoebo wrote: »

Answer:

let y+4/y = m

m^2 -9m +20=0
(m-5)(m-4)
m-5=0
m=5

m-4=0
m=4

y+4/y=5

y^2 +4=5y (i multiplied across by y to remove the fraction)
y^2 -5y + 4=0

(y-4)(y-1)
y-4=0
*y=4*

y-1=0
*y=1*

y+4/y=4
y^2 +4= 4/y
y^2 -4y +4=0
(y-2)(y-2)
y-2=0
*y=2*

Hope that helps!

Adding the M was such a smart move. Didn't think of it that way, but it makes sense.

Nice Job

phoebo · 05-10-2014 11:06PM

DublinArnie wrote: »

Adding the M was such a smart move. Didn't think of it that way, but it makes sense.

Nice Job

Thank you, it helped that we have just covered this topic in class! :-)

iCrazzy · 05-10-2014 11:07PM

phoebo wrote: »

Answer:

let y+4/y = m

m^2 -9m +20=0
(m-5)(m-4)
m-5=0
m=5

m-4=0
m=4

y+4/y=5

y^2 +4=5y (i multiplied across by y to remove the fraction)
y^2 -5y + 4=0

(y-4)(y-1)
y-4=0
*y=4*

y-1=0
*y=1*

y+4/y=4
y^2 +4= 4/y
y^2 -4y +4=0
(y-2)(y-2)
y-2=0
*y=2*

Hope that helps!

Yes thank you so much mate.
Thought I would never get it.

LC Off Topic Thread (2015/16)

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