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APPLIED MATHS LEAVING CERT 2013

  • 07-09-2013 01:02PM
    #1
    Registered Users, Registered Users 2 Posts: 1


    in the leaving cert 2013 applied maths exam marking scheme,it says that the time if the first part of the journey is half(t-t1) ,how do you get that/why?


Comments

  • Registered Users, Registered Users 2 Posts: 5,671 ✭✭✭TheBody


    qwertboy2 wrote: »
    in the leaving cert 2013 applied maths exam marking scheme,it says that the time if the first part of the journey is half(t-t1) ,how do you get that/why?

    What question number and ordinary or higher level?


  • Moderators, Education Moderators Posts: 26,424 Mod ✭✭✭✭Peregrine


    You're going to have to be a bit more specific..

    But I assume you're talking about Q1 b in Higher Level?

    It says the total time is t seconds and the time spent travelling at a speed of v ms-¹ is t1.

    c173bae56551c861519feb610836c755.png

    That means the sum of the time spent accelerating and the time spent decelerating is (t-t1).

    Its acceleration from 0 to v was f ms-² and its deceleration from v to 0 was -f ms-² meaning the time spent accelerating was the same as the time spent decelerating so you divide (t-t1) by two.

    t = total time
    t1 = time spent at constant velocity
    t-t1 = sum of the time spent accelerating and the time spent decelerating.
    ½(t-t1) = the time spent accelerating
    ½(t-t1) = the time spent decelerating.


  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    ^^^ this, and for future reference there is an applied maths thread here.

    And would I be right in assuming this was you too?


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