***2015 LC Maths Paper 2 - Higher Level - June 8th***

mayway

How did it go for everyone?

OMGeary

Question 8 :-(

yoyojc

Definitely more like previous years... was alot more challenging than Paper 1

That question where you had to find the radius was SO hard...

I'm not disappointed but I'm not delighted either..

Magnate

I'm certain that I got 0 in question 7. 40 marks down the drain. Attempt marks if I'm lucky but it just wasn't clicking with me, even though I'm sure that I'll be kicking myself later.

Much harder than paper 1 but still a fair paper overall. I should pass it.

BlueWolf16

Reaction : wow.. okay..

Don't think I did too bad, the statistics and probability were straightforward, besides the P and Pn-1 parts. Q6 was decent.. Worst part was that Q7 about the 2 circles was basically a copy+paste from one of the questions in the exam papers, and stupid me didn't look over it in the morning thinking it was too specific... God damnit.

Overall the 25markers were ok, Long q. pretty crappy. Q7 will be full of pity marks, Q8 was meh, Q9 2/3rds pity marks. Here's me hoping my P1 brings it up overall.

MmmPancakes

wtf that probability long question? got most of it out but didn't get to finish the > 0.00000000001 one part and the part after. Went well though, hoping for an A

Chef Tony

"Ah a nice easy probability question at the start, glad its there. Thats my worst topic out of the way. Can't wait for that 50 marker statistics!."

"Oh. It's a short question. Hrmm. Maybe they are going to have it as a short and long section."

"Oh... its a !!!65!!! mark question on probability. Might just off myself right now"

Bartekm1996

Wasn't hard or easy, much tougher than paper 1.The basketball question was though. The circle question almost got it but it wasn't easy.

is mise spartacus

Question 7 was a disaster
Think I said 11 for the radius

Fiona G

Was happy with that but felt more confident with paper 1. Got 20 for that radius, anyone else get that?

Quarks

A complete disaster. I was only able to really do about 3 or 4 questions, the rest are all attempts and guesses.

Genuinely has me thinking I failed.

Magnate

Nooo I just realised I did the construction wrong

Aoife37

Fiona G wrote: »

Was happy with that but felt more confident with paper 1. Got 20 for that radius, anyone else get that?

Got 20 for the radius and something like 21290cm for total area

AnnaCU

I got 2.25 for the radius :P am I the only one?

simplyno1

Q1 probability was alright.. didn't get p values in Q2. didn't get the value of k in q3. got q4, didn't get the trig proof in q6. didnt get the total area in q7, or the angle. got a good bit of q8 except for the second last and third last part. ran out of time after doing first two parts of q9 ... **** life

Bartekm1996

Fiona G wrote: »

Was happy with that but felt more confident with paper 1. Got 20 for that radius, anyone else get that?

Got 19.1

SteveZissou

Anyone get 9.999 (basically 10) for h, the height of the tree above the horizontal? I spent ages on that question until I realised it gave you the value for theta!

simplyno1

Im so pissed... didn't realise the exam was 2:30hr, I intended to leave Q5 and Q9 till the last 20mins and as i was working through the probability question the superintendent just goes "you have 5 minutes left" oh my god..... managed to scrabble a few things down.. godsake!

The_N4sir

SteveZissou wrote: »

Anyone get 9.999 (basically 10) for h, the height of the tree above the horizontal? I spent ages on that question until I realised it gave you the value for theta!

Yes I got 10 aswell.

Question 7 i did quite well but stupid me forgot that it was 3r instead of 4r for the first part to find the value of r. Is that most of the marks for the rest of the question gone? I would have got nearly full marks aswell:(

AnnaCU

SteveZissou wrote: »

Anyone get 9.999 (basically 10) for h, the height of the tree above the horizontal? I spent ages on that question until I realised it gave you the value for theta!

I think I got 10 as well

SteveZissou

The_N4sir wrote: »

Question 7 i did quite well but stupid me forgot that it was 3r instead of 4r for the first part to find the value of r. Is that most of the marks for the rest of the question gone? I would have got nearly full marks aswell:(

I'd say you'll be fine once your methods were correct for the following few parts, I'd say a lot of people left it as 4r

expiiplus1

The_N4sir wrote: »

Yes I got 10 aswell.

Question 7 i did quite well but stupid me forgot that it was 3r instead of 4r for the first part to find the value of r. Is that most of the marks for the rest of the question gone? I would have got nearly full marks aswell:(

No way. At most you'll lose 3 marks. Since it was a hard-ish paper, you'll probably lose less, 1 perhaps.

PotmBottom

Yeah I got 10 as well. I'm kicking myself over the blunder I made in Q7, I took the wrong side of the triangle as the Hypotenuse! As far as I know you only get penalised once for a mistake like that? Would suck to lose marks over something so silly multiple times over.

Benm123

For question 7, I got r=2root10. Am I the only one? I did the identical question to it in the exam papers yesterday and followed the same method which I'm more than certain is correct, but everyone else got different values for r!

mayway

No, you should be fine. It won't mean that the rest of the question is marked wrong.

PotmBottom

I can't remember what the exact value of the hypotenuse is, but the equation is (8r)^2 + (3r)^2 = (whatever that number was)^2

at least that's what I did.

simplyno1

can anyone tell me how you found the value of k in the line question? it said P(10, K) was a bisector of the angle between line 1 and line 2... does that mean the perpendicular distance from P->line 1 was equal to perp. distance from P->line 2? and you let the two equal and get 2 values for K?

Ansum

What was wrong with that question with the golf ball through the air. That question was like something for applied maths students. I don't like this at all. Maths should be a subject (mostly) taught on its own, just like any other subject.

r00d

I honestly thought that was appalling overall, and I see that most of us got different answers etc. but just remember that apparently they can only deduct you marks once for an incorrect answer, so if you carry a wrong answer through the other parts of a question, you're giving yourself the chance of getting full marks or high attempt marks, as long as your method was right, or so my teacher has been saying for the past 2 years lol don't give me death if i'm wrong here

The_N4sir

simplyno1 wrote: »

can anyone tell me how you found the value of k in the line question? it said P(10, K) was a bisector of the angle between line 1 and line 2... does that mean the perpendicular distance from P->line 1 was equal to perp. distance from P->line 2? and you let the two equal and get 2 values for K?

That was a hard question even some of the best guys in my class did not get it. I don't even remember what i did but i should get some decent attempt marks

Doctorhopeful

Radius was definitely 20cm guys. Thought it was a really good paper. Only thing i couldn't get was showing how pn+1=0.6 +0.2pn, but using that equation i could prove the next parts. Questions 7, the final area was about 28,000cm^2. Very happy, but it was definitely harder than p2.

Peregrine

Can someone describe this question? The paper won't be up online til 6pm.

Ansum wrote: »

What was wrong with that question with the golf ball through the air. That question was like something for applied maths students. I don't like this at all. Maths should be a subject (mostly) taught on its own, just like any other subject.

Doctorhopeful

The_N4sir wrote: »

That was a hard question even some of the best guys in my class did not get it. I don't even remember what i did but i should get some decent attempt marks

Yep you had to equate the two perpendicular distances, i got 3/4 and -48.

PotmBottom

Ansum wrote: »

What was wrong with that question with the golf ball through the air. That question was like something for applied maths students. I don't like this at all. Maths should be a subject (mostly) taught on its own, just like any other subject.

It kind of is, but we'd have to account for gravity and boring things like vertical and horizontal components of gravity and it's a bunch of fun!. What did you get stuck on?

The_N4sir

Ansum wrote: »

What was wrong with that question with the golf ball through the air. That question was like something for applied maths students. I don't like this at all. Maths should be a subject (mostly) taught on its own, just like any other subject.

Yeah I do applied maths and i was thinking the same. I was trying to do it like an applied maths question but i had to restart the question again since my answers were definitely wrong

fin709

The basketball question was very confusing, the first two bits we didnt know were the throws in seperate groups or straight after each other so didnt know whether to use bernoulli trials or not. Used bernoulli trials in the end, im pretty sure i did it wrong

Benm123

Doctorhopeful wrote: »

Radius was definitely 20cm guys. Thought it was a really good paper. Only thing i couldn't get was showing how pn+1=0.6 +0.2pn, but using that equation i could prove the next parts. Questions 7, the final area was about 28,000cm^2. Very happy, but it was definitely harder than p2.

How did you arrive at that radius? I did the correct method, I think, squaring 3r and 8r and letting it equal to square (value for hyp) and i got 2root10?

Doctorhopeful

Nim wrote: »

Can someone describe this question? The paper won't be up online til 6pm.

Given the equation of the flight path for a golf ball. Then given the horizontal speed, had to work out the angle of elevation between where it landed and where it was hit from. Was very like a projectile question from app maths

PotmBottom

Nim wrote: »

Can someone describe this question? The paper won't be up online til 6pm.

we were given a slope, and the height of the ball was given by a quadratic equation. Think it was 6t^2+22t+8 or something, we were asked to find the height of the ball at t=0. Which was 8. Then it told us that the horizontal speed of the ball is 38m/s. We were then asked for the angle of inclination. so I let the equation equal zero and got t =4 so I multipled 38(4) to get 152. then the tan inverse of 8/152 was equal to the angle of inclination = 3 degrees.

Doctorhopeful

Benm123 wrote: »

How did you arrive at that radius? I did the correct method, I think, squaring 3r and 8r and letting it equal to square (value for hyp) and i got 2root10?

9r^2 plus 64r^2 = 29200
R^2 = 400
r= 20

EDIT: oh and 20root73 squared is 29200

Ansum

Nim wrote:

Can someone describe this question? The paper won't be up online til 6pm.

.
Sorry Nim but the question was is confusing to me that it's a blur, but hopefully someone will post it.

Doctorhopeful

Benm123 wrote: »

How did you arrive at that radius? I did the correct method, I think, squaring 3r and 8r and letting it equal to square (value for hyp) and i got 2root10?

I think you forgot a zero as root40 is 2root10 but root400 is 20

Kremin

simplyno1 wrote: »

can anyone tell me how you found the value of k in the line question? it said P(10, K) was a bisector of the angle between line 1 and line 2... does that mean the perpendicular distance from P->line 1 was equal to perp. distance from P->line 2? and you let the two equal and get 2 values for K?

Find point intersection 2 lines. Find angle between then. Divide angle by two. Use tan formula again to find angle between bisector (1/2 angle) and any of the lines. This will give you the slope of the bisector. Use then y-y1 formula on the point if intersection. Sub 10, k in.

Fiona G

Nim wrote:

Can someone describe this question? The paper won't be up online til 6pm.

It gave a formula for the height of a golf ball above the flat, something like h=-6tsquared + 30t + 20 (can't remember values) where t is the seconds since the ball was hit. It wasn't really like an applied maths question, just had to let h=0 to find t etc.

Doctorhopeful

fin709 wrote: »

The basketball question was very confusing, the first two bits we didnt know were the throws in seperate groups or straight after each other so didnt know whether to use bernoulli trials or not. Used bernoulli trials in the end, im pretty sure i did it wrong

Pretty sure you couldn't use benoulli trials because the trials weren't independent ie the previous throws affected the one you're doing

Kremin wrote: »

Find point intersection 2 lines. Find angle between then. Divide angle by two. Use tan formula again to find angle between bisector (1/2 angle) and any of the lines. This will give you the slope of the bisector. Use then y-y1 formula on the point if intersection. Sub 10, k in.

I did this and it got a really horrible answer, but then equating two perpendicular equations together got k= 3/4 and -48

fin709

Doctorhopeful wrote: »

Pretty sure you couldn't use benoulli trials because the trials weren't independent ie the previous throws affected the one you're doing

But it said first throws so i presumed they were seperate groups of first throws so every one of them was 0.7

Peregrine

Doctorhopeful wrote: »

Given the equation of the flight path for a golf ball. Then given the horizontal speed, had to work out the angle of elevation between where it landed and where it was hit from. Was very like a projectile question from app maths

PotmBottom wrote: »

we were given a slope, and the height of the ball was given by a quadratic equation. Think it was 6t^2+22t+8 or something, we were asked to find the height of the ball at t=0. Which was 8. Then it told us that the horizontal speed of the ball is 38m/s. We were then asked for the angle of inclination. so I let the equation equal zero and got t =4 so I multipled 38(4) to get 152. then the tan inverse of 8/152 was equal to the angle of inclination = 3 degrees.

Fiona G wrote: »

It gave a formula for the height of a golf ball above the flat, something like h=-6tsquared + 30t + 20 (can't remember values) where t is the seconds since the ball was hit. It wasn't really like an applied maths question, just had to let h=0 to find t etc.

Now, I haven't actually seen it but it sounds similar to a question in one of the Text and Tests books.

expiiplus1

simplyno1's solution also works and is a lot nicer than the other way of solving it. I was kicking myself for doing it the horrid way.
By the way Kremin, things work out a lot easier if you convert tan to angles.

Benm123

Doctorhopeful wrote: »

9r^2 plus 64r^2 = 29200
R^2 = 400
r= 20

EDIT: oh and 20root73 squared is 29200

Ah balls I did that same way must have made a numerical error

Fiona G

Doctorhopeful wrote:

I did this and it got a really horrible answer, but then equating two perpendicular equations together got k= 3/4 and -48

I got this too!

Doctorhopeful

fin709 wrote: »

But it said first throws so i presumed they were seperate groups of first throws so every one of them was 0.7

Why would they give the other information then? Seems like an oversimplification but obviously i can't be certain