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** Higher Level Maths Paper 1 2012 Before/After **

11213141517

Comments

  • Registered Users, Registered Users 2 Posts: 414 ✭✭Dicksboro_man


    Lads in 1b(ii) i effectively made a cubic whose roots are 1 more instead of 1 less...
    how many marks do ye think i'll lose? i mean, will it qualift as a blunder? :confused::(


  • Registered Users, Registered Users 2 Posts: 102 ✭✭Tankosaur


    nmd64 wrote: »
    Do you reckon leaving it as 4ln(7) will be a slip or blunder or will they accept it as full marks?


    4ln7 is correct but ln28 is wrong

    when you multiply a power you can bring in the number as a power not a multiple.

    The correct answer would be ln7^4


  • Registered Users, Registered Users 2 Posts: 715 ✭✭✭Wesc.


    Lads in 1b(ii) i effectively made a cubic whose roots are 1 more instead of 1 less...
    how many marks do ye think i'll lose? i mean, will it qualift as a blunder? :confused::(

    You read the question wrong. But effectively carried out the same method and answered the question correctly. So, I think it would very harsh to dock you anything more than a mark.


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    Lads in 1b(ii) i effectively made a cubic whose roots are 1 more instead of 1 less...
    how many marks do ye think i'll lose? i mean, will it qualift as a blunder? :confused::(

    Probably a misreading, you should only lose a mark as it didn't oversimplify the question.


  • Registered Users, Registered Users 2 Posts: 414 ✭✭Dicksboro_man


    finality wrote: »
    Probably a misreading, you should only lose a mark as it didn't oversimplify the question.
    Wesc. wrote: »
    You read the question wrong. But effectively carried out the same method and answered the question correctly. So, I think it would very harsh to dock you anything more than a mark.

    ah no, you see lads what i did was i took the right answers from the part (i)
    and did something like this with them


    (x+2)-1= x+1

    (x-1) -1= x-2

    (x-3)-1= x-4

    and used those roots instead of
    x=-2-1= -3 (x+3)
    x=1-1=0 (x)
    x=3-1=2 (x-2)

    you know? :confused: kinda gutted here. ye still think that'll only lose me a mark or two?


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  • Closed Accounts Posts: 243 ✭✭Stalin and rugby


    ah no, you see lads what i did was i took the right answers from the part (i)
    and did something like this with them


    (x+2)-1= x+1

    (x-1) -1= x-2

    (x-3)-1= x-4

    and used those roots instead of
    x=-2-1= -3 (x+3)
    x=1-1=0 (x)
    x=3-1=2 (x-2)

    you know? :confused: kinda gutted here. ye still think that'll only lose me a mark or two?

    That almost caught me aswell, looks like blunder to me bro -3.


  • Registered Users, Registered Users 2 Posts: 715 ✭✭✭Wesc.


    ah no, you see lads what i did was i took the right answers from the part (i)
    and did something like this with them


    (x+2)-1= x+1

    (x-1) -1= x-2

    (x-3)-1= x-4

    and used those roots instead of
    x=-2-1= -3 (x+3)
    x=1-1=0 (x)
    x=3-1=2 (x-2)

    you know? :confused: kinda gutted here. ye still think that'll only lose me a mark or two?

    Ah so you took 1 from the factors.. that's a tough one to call alright. You do realise the max you could lose is 3 marks though? So it's not too bad. Personally, I'd classify that as a blunder.


  • Registered Users, Registered Users 2 Posts: 14 Theorems



    ah no, you see lads what i did was i took the right answers from the part (i)
    and did something like this with them


    (x+2)-1= x+1

    (x-1) -1= x-2

    (x-3)-1= x-4

    and used those roots instead of
    x=-2-1= -3 (x+3)
    x=1-1=0 (x)
    x=3-1=2 (x-2)

    you know? :confused: kinda gutted here. ye still think that'll only lose me a mark or two?



    I did the exact same, so annoyed at myself
    Hopefully they won't be too mean :/


  • Registered Users, Registered Users 2 Posts: 414 ✭✭Dicksboro_man


    Wesc. wrote: »
    Ah so you took 1 from the factors.. that's a tough one to call alright. You do realise the max you could lose is 3 marks though? So it's not too bad. Personally, I'd classify that as a blunder.
    That almost caught me aswell, looks like blunder to me bro -3.
    thanks lads, i was starting to get worried but 3 marks aint TOO bad...was hoping for full marks in paper 1 to give me a nice cushion for paper 2 (got 98% in P1 in the mocks, only 85% in P2) but ah well :) cheers again :o


  • Closed Accounts Posts: 243 ✭✭Stalin and rugby


    yo-dawg-i-hear-u-have-trouble-undestanding-math-and-science.jpg


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  • Registered Users, Registered Users 2 Posts: 217 ✭✭RedTexan


    All that was required in question 4 (c) was to find b^2=ac using the common ratio and then use this to show the common difference in the arithmetic series was equal, right?


  • Registered Users, Registered Users 2 Posts: 217 ✭✭RedTexan


    And for question 6 (c) (ii) was f'(x)=8cos^2(2x)+8cos(2x)+4? And for getting this far and making an equation with y=cos(2x) but going no further how many marks do ye reckon I'd get? I know it's anybody's guess, but just for a small bit of peace of mind!


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    RedTexan wrote: »
    All that was required in question 4 (c) was to find b^2=ac using the common ratio and then use this to show the common difference in the arithmetic series was equal, right?

    Yup. That's how I'd have done it... :'(


  • Registered Users, Registered Users 2 Posts: 568 ✭✭✭Dapics


    Hey guys need your help.

    For 2.C , I misread the damn question and for some damn reason when i multiplied across by x , i had x^2 + x =2x, i brought across the 2x and argued my case that it must be greater than zero.... i did this for both part i, and part ii, i am very very annoyed with myself, this is without a doubt the reason i will not get a b3 in my maths :(

    I'm just wondering what marks will I get for each answer?

    For c, part iii, i think i got that one right.


  • Closed Accounts Posts: 243 ✭✭Stalin and rugby


    Dapics wrote: »
    Hey guys need your help.

    For 2.C , I misread the damn question and for some damn reason when i multiplied across by x , i had x^2 + x =2x, i brought across the 2x and argued my case that it must be greater than zero.... i did this for both part i, and part ii, i am very very annoyed with myself, this is without a doubt the reason i will not get a b3 in my maths :(

    I'm just wondering what marks will I get for each answer?

    For c, part iii, i think i got that one right.

    -1 as long as the question was not oversimplified


  • Registered Users, Registered Users 2 Posts: 568 ✭✭✭Dapics


    -1 as long as the question was not oversimplified

    You serious?

    But the right answer is that any no. squared is greater than zero, i having made this huge blunder without recognising it argued that any no squared (sub no. in for x squared) plus a number (sub no in for x) is greater than zero....

    Did it this way twice, taking into account my blunder, i would think the way i progressed with the question I was actually right in my hypotheses...

    But I dont really know, are you sure it would be -1 off the answer?


  • Registered Users, Registered Users 2 Posts: 568 ✭✭✭Dapics


    Helloxoxo wrote: »
    It's definitely not a slip.. Probably blunder at least

    So I take it that 3 off the answer?


  • Registered Users, Registered Users 2 Posts: 143 ✭✭Killian In The Name Of


    As a Pass Maths student, reading this thread is making me feel slightly nauseous...


  • Registered Users, Registered Users 2 Posts: 217 ✭✭RedTexan


    For question 6 (c) (ii) was f'(x)=8cos^2(2x)+8cos(2x)+4? And for getting this far and making an equation with y=cos(2x) but going no further how many marks do ye reckon I'd get? I know it's anybody's guess, but just for a small bit of peace of mind!


  • Closed Accounts Posts: 243 ✭✭Stalin and rugby


    Dapics wrote: »
    So I take it that 3 off the answer?

    You gotta stop worrying about that stuff bro, like I said if the question isn't oversimplified and the method is correct where you just wrote down the wrong number or whatever it's -1.

    But tbh none of us can tell you for certain, forget maths p1 go take a tug get up early tomorrow morning, head down paper 2 bro Gotta work! :D


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  • Closed Accounts Posts: 243 ✭✭Stalin and rugby


    RedTexan wrote: »
    For question 6 (c) (ii) was f'(x)=8cos^2(2x)+8cos(2x)+4? And for getting this far and making an equation with y=cos(2x) but going no further how many marks do ye reckon I'd get? I know it's anybody's guess, but just for a small bit of peace of mind!

    Part c will probs be 20 marks. 10 marks for differentiating correctly 5 for expressing in cos2x and 5 for the > 0 bit. Depends how everyone else does though


  • Registered Users, Registered Users 2 Posts: 568 ✭✭✭Dapics


    You gotta stop worrying about that stuff bro, like I said if the question isn't oversimplified and the method is correct where you just wrote down the wrong number or whatever it's -1.

    But tbh none of us can tell you for certain, forget maths p1 go take a tug get up early tomorrow morning, head down paper 2 bro Gotta work! :D

    Shall do, I'm hoping to get an A2 in Paper 2, know co-ords,circle and trig off to a tee and know all theorems.... just need to focus on probability... thanks for your help man!


  • Registered Users, Registered Users 2 Posts: 217 ✭✭RedTexan


    Part c will probs be 20 marks. 10 marks for differentiating correctly 5 for expressing in cos2x and 5 for the > 0 bit. Depends how everyone else does though
    Yeah, hopefully I'll get 45 and maybe a couple of attempt marks there. Might just push me into solid A1 territory


  • Registered Users, Registered Users 2 Posts: 217 ✭✭RedTexan


    Part c will probs be 20 marks. 10 marks for differentiating correctly 5 for expressing in cos2x and 5 for the > 0 bit. Depends how everyone else does though
    Was that the correct answer for the expression of f'(x) though?


  • Registered Users, Registered Users 2 Posts: 55 ✭✭WestIRL


    What classifies as an attempt mark? For lets say...... Q8 C (ii)? Or in Q2 B (ii) I was literally staring at X^2 + 2x + 1 and JUST SIMPLY COULD NOT THINK OF ITS FACTORS!!! I mean surely the examiner might throw me like 2 marks for that?


  • Registered Users, Registered Users 2 Posts: 58 ✭✭Epsi


    WestIRL wrote: »
    What classifies as an attempt mark? For lets say...... Q8 C (ii)? Or in Q2 B (ii) I was literally staring at X^2 + 2x + 1 and JUST SIMPLY COULD NOT THINK OF ITS FACTORS!!! I mean surely the examiner might throw me like 2 marks for that?

    An attempt mark is performing the first step correctly in solving a problem.


  • Registered Users, Registered Users 2 Posts: 217 ✭✭RedTexan


    WestIRL wrote: »
    What classifies as an attempt mark? For lets say...... Q8 C (ii)? Or in Q2 B (ii) I was literally staring at X^2 + 2x + 1 and JUST SIMPLY COULD NOT THINK OF ITS FACTORS!!! I mean surely the examiner might throw me like 2 marks for that?
    I'm hoping to get maybe 17 out of 20 for getting that far! I just frantically wrote that down and said it must be greater than zero, I hope I didn't scribble over in the heat of the moment


  • Closed Accounts Posts: 113 ✭✭Izymunz


    I need 85%.


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    RedTexan wrote: »
    For question 6 (c) (ii) was f'(x)=8cos^2(2x)+8cos(2x)+4? And for getting this far and making an equation with y=cos(2x) but going no further how many marks do ye reckon I'd get? I know it's anybody's guess, but just for a small bit of peace of mind!

    Yeah that's correct.


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  • Registered Users, Registered Users 2 Posts: 18 liamduffy1994


    ah no, you see lads what i did was i took the right answers from the part (i)
    and did something like this with them


    (x+2)-1= x+1

    (x-1) -1= x-2

    (x-3)-1= x-4

    and used those roots instead of
    x=-2-1= -3 (x+3)
    x=1-1=0 (x)
    x=3-1=2 (x-2)

    you know? :confused: kinda gutted here. ye still think that'll only lose me a mark or two?
    Did the same mate, was scribbling it at the end so Im happy with anything at all they give me


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