Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie

Thermaskirt / Climaboard / Thermodul

Options

Comments

  • Registered Users Posts: 45,861 ✭✭✭✭muffler


    Theres also a small mention of this type of heating system in this thread.


  • Registered Users Posts: 15,944 ✭✭✭✭Villain


    Seems expensive using the program that you can download, one of the small bedrooms in my house, 3m x 4.3m its €800 for the skirting rad!!!


  • Closed Accounts Posts: 2,290 ✭✭✭ircoha


    BB, no idea on cost, but just a few thoughts on the 'math'

    from the site
    <<Because ThermaSkirt® is made from an alloy that is 5 times more effective at passing heat than steel.>> my emphasis

    We need to be clear on what we mean by passing heat.

    As we all remember from our school days, heat moves from a warmer body to a colder body in 3 ways
    1 conduction
    2 convection
    3 radiation

    the thermal conductivity
    http://www.engineeringtoolbox.com/thermal-conductivity-d_429.html

    of Alu is much better than steel so the heat gets transferred to the Alu from the water better than if steel.
    The issue here is the ability to radiate heat which is generally measured by the coefficient of emissivity
    http://www.engineeringtoolbox.com/emissivity-coefficients-d_447.html

    The radiation energy per unit time from a body is a function of
    the surface area
    the surface temperature and
    the emissivity.

    This is the formula for calculating The Net Radiation Loss Rate

    << If an hot object is radiating energy to its cooler surroundings the net radiation heat loss rate can be expressed like
    q = ε (Th**4 - Tc**4) Ac
    where
    Th = hot body absolute temperature (K)
    Tc = cold surroundings absolute temperature (K)
    Ac = area of the object (m2)
    ε = emissivity of the object [ the range is 0 to 1, with 1 being best]

    Now you will see from the table of co-efficients of emissivity that paint is 0.96 so a painted Alu rad should work very well, assuming the heat transfer from the Alu to the paint works well.

    The importance of the temperature in the formula is clear from the fact that it is to the power of 4 so low temp water from a heat pump might not work because the surface area may not be large enough.

    My one concern is that it seems to fit tight against the wall so how much of the heat gets lost there: need to have it very well insulated and put Alu foil tape on behind.


Advertisement