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** LC Applied Maths 2014 - Before and after discussion **

24

Comments

  • Registered Users Posts: 1,645 ✭✭✭Daniel2590


    otpmb wrote: »
    Oh, if you break forces up into horizontal and vertical components in q4 on your diagram make sure you do it in different colours (i.e the force in one colour and its' components in another colour) otherwise it's treated as a mistake because you've got the same force in twice. I know this because my teacher corrects the papers every year, and he warned us that loads of people lose marks over this.

    Or you can draw a broken line if you want I'm fairly sure


  • Registered Users Posts: 98 ✭✭WoolyAbyss


    Does anyone know if projectiles on an inclined plane is on the ordinary course?


  • Registered Users Posts: 541 ✭✭✭TheBegotten


    Hands up who's going to have a nervous breakdown if Q5 is the same as last year? Just me? Seriously though, they've been adding different approaches to the standard questions in the last few years. Wedges are overdue, an overtaking question for 1b is due, a U-tube question for 9 is probably due as well. Don't take anything for granted and be prepared to deviate from the usual methods and think on your feet.


  • Registered Users Posts: 137 ✭✭Nicke011


    I don't know if I'm tired or what, but I feel like I forgot everything and that I'm going to fail :o I'm looking at the questions in my folder and I can't understand them :(


  • Registered Users, Registered Users 2 Posts: 881 ✭✭✭AtomicKoala


    be prepared to deviate from the usual methods and think on your feet.

    Oh god no :(


  • Registered Users, Registered Users 2 Posts: 906 ✭✭✭Ompala


    Hands up who's going to have a nervous breakdown if Q5 is the same as last year? Just me? Seriously though, they've been adding different approaches to the standard questions in the last few years. Wedges are overdue, an overtaking question for 1b is due, a U-tube question for 9 is probably due as well. Don't take anything for granted and be prepared to deviate from the usual methods and think on your feet.
    Oh god no :(

    In fairness the stuff you listed there isn't the worst in the world either, U-Tube questions are nice, I was hoping one would appear on my exam :)
    Don't panic in the exam anyways lads, if you stay calm you will be able to pick up majority of the marks by completing your method


  • Registered Users Posts: 541 ✭✭✭TheBegotten


    Also, I've forgotten to post this incredibly valuable piece of advice/motivation. Good luck! http://www.smbc-comics.com/?id=3011


  • Registered Users Posts: 84 ✭✭otpmb


    Daniel2590 wrote: »
    Or you can draw a broken line if you want I'm fairly sure

    oh yeah that's fine too you just have to differentiate between the force and its components.


  • Registered Users Posts: 20 PhysicsKid99


    Anyone get k=15? :/


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  • Registered Users Posts: 27 c0unterpart


    didnt like that at all.No chance of an A now but sure.

    how the hell do you prove tanA < tan B ?


  • Registered Users Posts: 20 PhysicsKid99


    didnt like that at all.No chance of an A now but sure.

    how the hell do you prove tanA < tan B ?

    I said vx>0 at range, so then I ended up getting 1>0 and then TanA< TanB. It made sense when I did it out...


  • Registered Users, Registered Users 2 Posts: 906 ✭✭✭Ompala


    And now the wait for SEC to upload the paper is on...


  • Closed Accounts Posts: 126 ✭✭RedSeven7


    didnt like that at all.No chance of an A now but sure.

    how the hell do you prove tanA < tan B ?

    Haven't a clue! :confused:
    I thought that paper was really tough :/


  • Moderators, Education Moderators Posts: 26,403 Mod ✭✭✭✭Peregrine


    :(

    I even screwed up the pulley question.


  • Registered Users, Registered Users 2 Posts: 4,881 ✭✭✭TimeToShine


    What time will the paper be up?

    Wouldn't mind a look for old times sake


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  • Moderators, Education Moderators Posts: 26,403 Mod ✭✭✭✭Peregrine


    What time will the paper be up?

    Wouldn't mind a look for old times sake

    Around 5 or 6pm. I could take a picture of some questions when I get home if you want.


  • Registered Users Posts: 68 ✭✭Delightfully Bright


    Everyone I was talking to said it was a tough paper. I'd say they'll be nice in the marking scheme or else applied maths might lose its huge A1 rate.


  • Registered Users Posts: 136 ✭✭FHB


    At least other people found it tough too...


  • Registered Users Posts: 41 Solid_Shepard


    To say that was terrible would be an understatement.

    Question 1 was alright. The b part was fairly easy, but I couldn't get (ii) as I forgot what to do.

    Question 2 was...less alright. The a part was absolutely terrible, to say the least; I can't remember a single time something like that came up. The b part was fine.

    Question 3 was ok. The a part was tricky and really time-consuming, while the b part was ok. The (ii) was very tricky, I thought, and I was forced to move on past it due to the time.

    Question 4 was...well...I don't like that diagram so didn't do it. It looks very tricky. The b part seems alright.

    Question 5 wasn't too bad in terms of maths, but finding the co-efficient of restitution took so long that there was ample room to slip-up, and I ended up making an error in the maths which had a knock on effect.

    Question 6 I didn't like. The first part was a tricky way for them to ask to prove Simple Harmonic Motion. I ended up making an error looking at it now though, as I used the "four" instead of "one over four" which was a stupid error. This had a knock on effect on the second part. The b part I didn't like either. The first part was kind of ok, but I only just noticed that I completely misread the (ii) so that went terribly too.

    Question ten seemed ok. I'm worried that I thought it went ok.

    Overall, I had been expecting an A1; now, I am not.

    EDIT: Ok, so under the absolutely worst case scenario, where each part is 25 marks, an i part is 15, and an ii part is ten, and they remove all of the marks for an incorrect answer, I would be down to 235/300. I don't think it'll be marked that harshly, so maybe I got a B1 pushing it which is better than I thought. I'm not hopeful though.


  • Registered Users Posts: 20 PhysicsKid99


    K=15 anyone?


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  • Registered Users, Registered Users 2 Posts: 4,881 ✭✭✭TimeToShine


    Nimrod 7 wrote: »
    Around 5 or 6pm. I could take a picture of some questions when I get home if you want.

    Ah it's alright i'll wait around for it. The physics paper looked lovely so I was wondering would this one be a walk in the park as well - apparently not!


  • Registered Users Posts: 10 jimbob95


    Anyone else feel like they will be lucky to pass after feeling beforehand like they would get at least a B? :/


  • Registered Users Posts: 68 ✭✭Delightfully Bright


    jimbob95 wrote: »
    Anyone else feel like they will be lucky to pass after feeling beforehand like they would get at least a B? :/

    I haven't heard of anyone yet who liked the paper so don't give up yet. They'll throw attempt marks at us to keep the high A rate.


  • Registered Users, Registered Users 2 Posts: 232 ✭✭MegGustaa


    RedSeven7 wrote: »
    Haven't a clue! :confused:
    I thought that paper was really tough :/

    I used the expression for Tan A from the first part (which was in terms of Tan B) and put it < Tan B and went from there, ended up with a line like Tan B > 0 which is true if B is an acute angle, which I guess it has to be.

    Very rough paper. Was hoping for an A1, now I'll be lucky to get a B1/B2. Oh well. Didn't need Applied Maths for points, realistically I was only doing it to get a head start on mechanics for 3rd level.


  • Registered Users, Registered Users 2 Posts: 881 ✭✭✭AtomicKoala


    Well there goes my A :(


  • Registered Users Posts: 27 c0unterpart


    Well there goes my A :(

    same.

    HIGH FIVE !


  • Moderators, Education Moderators Posts: 26,403 Mod ✭✭✭✭Peregrine


    Ah it's alright i'll wait around for it. The physics paper looked lovely so I was wondering would this one be a walk in the park as well - apparently not!

    .


  • Registered Users Posts: 25 Shanrahan


    I got k=32?... :/


  • Registered Users, Registered Users 2 Posts: 906 ✭✭✭Ompala


    For Q 9
    (a) 3200 and 4800 kg/m^3
    (b) (i) x = 45.18 cm (or to be exact, x^2 = 100,000/49)
    (ii) Tension = 160 N
    (iii) Density = 428.157 kg/m^3 ( or 3000/7 kg/m^3)


  • Closed Accounts Posts: 126 ✭✭RedSeven7


    For Question 4(a) - the pulley - does anyone know if the acceleration of A and B is the same, or if the acceleration of B a multiple of the acceleration of A or vice versa?? :confused:


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  • Registered Users Posts: 137 ✭✭Nicke011


    wF2DcQb.png


  • Registered Users Posts: 25 Shanrahan


    RedSeven7 wrote: »
    For Question 4(a) - the pulley - does anyone know if the acceleration of A and B is the same, or if the acceleration of B a multiple of the acceleration of A or vice versa?? :confused:

    Yeah they should be the same and then force equals mass times acceleration


  • Registered Users Posts: 137 ✭✭Nicke011


    RedSeven7 wrote: »
    For Question 4(a) - the pulley - does anyone know if the acceleration of A and B is the same, or if the acceleration of B a multiple of the acceleration of A or vice versa?? :confused:
    Shanrahan wrote: »
    Yeah they should be the same and then force equals mass times acceleration

    I think it's all one acceleration a... And I used T for all tensions throughout the string cause it's only one string.


  • Registered Users Posts: 20 PhysicsKid99


    Nicke011 wrote: »
    I think it's all one acceleration a... And I used T for all tensions throughout the string cause it's only one string.

    I used a and 2a because A had two strings attached... Oops


  • Registered Users, Registered Users 2 Posts: 232 ✭✭MegGustaa


    I used a and 2a because A had two strings attached... Oops

    I had the accln of B was half that of A because when A moves forward, the length of the string string both gets longer and shorter because of the way it's set up, so B only moves up half the distance that A moves forwards. Don't really know what I was thinking tbh.


  • Closed Accounts Posts: 367 ✭✭qweerty


    The hanging-block's acceleration is twice that of the other...unless this sun is doing weird things to my head. If I'm wrong, you won't notice I'm blushing cause this sun is doing weird things to my face.


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    That was a tough paper and pretty out there. Still, apart from question 5 (b) I think I got the answers. Questions 2 and 10 were nice, and though 3 had some trig manipulation, it was fairly basic stuff otherwise. To prove tan B > tan a here's how:

    (1+2tan*2B) (tan a) = tan B (taking the bottom off the right hand side and multiplying it by the left.

    Therefore if 1+2tan*2B is greater than 1 tan B is greater than tan a (because multipling it by more than one means you get a bigger number).

    To prove: 1+2tan*2B>1
    2tan*2B>0
    tan*2B>0
    (tanB)*2>0 true because (real)*2 > 0.


  • Registered Users Posts: 137 ✭✭Nicke011


    qweerty wrote: »
    The hanging-block's acceleration is twice that of the other...unless this sun is doing weird things to my head. If I'm wrong, you won't notice I'm blushing cause this sun is doing weird things to my face.
    I actually think you're right...
    Fu*k it anyway :(
    matthew8 wrote: »
    That was a tough paper and pretty out there. Still, apart from question 5 (b) I think I got the answers. Questions 2 and 10 were nice, and though 3 had some trig manipulation, it was fairly basic stuff otherwise. To prove tan B > tan a here's how:

    (1+2tan*2B) (tan a) = tan B (taking the bottom off the right hand side and multiplying it by the left.

    Therefore if 1+2tan*2B is greater than 1 tan B is greater than tan a (because multipling it by more than one means you get a bigger number).

    To prove: 1+2tan*2B>1
    2tan*2B>0
    tan*2B>0
    (tanB)*2>0 true because (real)*2 > 0.

    Please tell me are you a student or a teacher? ::D


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    Nicke011 wrote: »
    Please tell me are you a student or a teacher? ::D

    Student.

    For 4 part a indeed the acceleration of A is half acceleration B, got that one wrong but the same thing came up in 2008 and checked it just there.

    Anyone get the answer to 4 b part ii, I got 2.67 and 17.47 but no idea if it's right.


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  • Registered Users, Registered Users 2 Posts: 232 ✭✭MegGustaa


    qweerty wrote: »
    The hanging-block's acceleration is twice that of the other...unless this sun is doing weird things to my head. If I'm wrong, you won't notice I'm blushing cause this sun is doing weird things to my face.

    That actually makes so much sense. Damn. Oh well.


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    Other answers I got:
    1a i 24 -.5t*2
    ii 18.375

    b i : .53
    ii: 23.74

    2a ii 18:51
    b ii 91

    3a something like 12

    5a ii .84mu*2
    bi (pretty sure it's wrong) .77

    10 a i 4.22
    ii .33

    b i 1 and 2 seconds
    ii t*3 over 3+3t*2 over 2+2t+1
    iii 1 metre (could be wrong)


  • Registered Users, Registered Users 2 Posts: 232 ✭✭MegGustaa


    matthew8 wrote: »
    Other answers I got:
    1a i 24 -.5t*2
    ii 18.375

    b i : .53
    ii: 23.74

    2a ii 18:51
    b ii 91

    3a something like 12

    5a ii .84mu*2
    bi (pretty sure it's wrong) .77

    10 a i 4.22
    ii .33

    b i 1 and 2 seconds
    ii t*3 over 3+3t*2 over 2+2t+1
    iii 1 metre (could be wrong)

    I don't remember what I got for the other Qs but I got exactly the same for Q1a and Q10 :) a bit of a relief!


  • Registered Users, Registered Users 2 Posts: 906 ✭✭✭Ompala


    Q3 (a) I think its u = 4.9sqrt33 (or u = 28.148)
    Q10 a (i) v1 = 4.2248 m/s (ii) s = 0.330997 m
    b (i) Changes at 1 and 2 seconds (ii) s = (t^3)/3 - (3t^2)/2 + 2t + 1 (iii) 2/3 m
    matthew8 wrote: »
    Student.

    For 4 part a indeed the acceleration of A is half acceleration B, got that one wrong but the same thing came up in 2008 and checked it just there.

    Anyone get the answer to 4 b part ii, I got 2.67 and 17.47 but no idea if it's right.

    I got t = 0.267s and x = 14.5 cm, i don't think you converted from cm to m

    Then again I could be wrong too!


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    Ompala wrote: »
    Q3 (a) I think its u = 4.9sqrt33 (or u = 28.148)
    Q10 a (i) v1 = 4.2248 m/s (ii) s = 0.330997 m
    b (i) Changes at 1 and 2 seconds (ii) s = (t^3)/3 - (3t^2)/2 + 2t + 1 (iii) 2/3 m

    I think you've made a mistake on 10 b iii, integrating it like it was only one curve, but it was like a curve that went over and under so you had to do it for the first and the second second separately, which checks out because I got 1/6 metres for the second second, in case you didn't already know (I made a mistake too here, my answer on this threadis a correction on it).

    Just redid 3a and yeah that's the answer I got, not around 22.

    Sorry for all the post mortem lads, I can't help myself.
    Ompala wrote: »
    I got t = 0.267s and x = 14.5 cm, i don't think you converted from cm to m

    Then again I could be wrong too!

    The cm really caught me off guard there and I never dealt with it, but surely then my answer should be 100 times your answer?

    Anyway it should only be a blunder for me.


  • Registered Users, Registered Users 2 Posts: 906 ✭✭✭Ompala


    matthew8 wrote: »
    I think you've made a mistake on 10 b iii, integrating it like it was only one curve, but it was like a curve that went over and under so you had to do it for the first and the second second separately, which checks out because I got 1/6 metres for the second second, in case you didn't already know (I made a mistake too here, my answer on this threadis a correction on it).

    Just redid 3a and yeah that's the answer I got, not around 22.

    Sorry for all the post mortem lads, I can't help myself.
    matthew8 wrote: »
    The cm really caught me off guard there and I never dealt with it, but surely then my answer should be 100 times your answer?

    Anyway it should only be a blunder for me.

    Well spotted on Q10, annoyed at myself for missing that. But your answer makes sense though, as you are changing direction at 2 and 1 seconds (in my head anyway)

    Q3 was very strange, took me a while to cop it.

    Not 100 times as we had to take the square root, so thats why its off by 10 not 100


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  • Registered Users Posts: 20 PhysicsKid99


    T=0 and t= 3, anyone? I just said it changes when v=0 and integrated


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    Ompala wrote: »
    Well spotted on Q10, annoyed at myself for missing that. But your answer makes sense though, as you are changing direction at 2 and 1 seconds (in my head anyway)

    Q3 was very strange, took me a while to cop it.

    Not 100 times as we had to take the square root, so thats why its off by 10 not 100

    Good stuff, works out there I checked it. Anything for question 5? that's the only thing left in the post mortem really. Can't believe I messed up the 2 questions I find easiest usually, but the good news if they give you nearly all the marks for the equations in 4, and getting v1 and v2 in Q5, even though the lion's share of the time is spent doing the hard graft afterwards. As for the difference in the value of x in q4, did you take the acceleration of the wedge into account for the relative acceleration? Were we supposed to?


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    T=0 and t= 3, anyone? I just said it changes when v=0 and integrated

    Did you take into account that starting velocity was 2? That's where you would've gone wrong to get those. In fact I'm sure, because if you didn't your equation would have been t*2 -3t, which gives 0 and 3.


  • Registered Users Posts: 20 PhysicsKid99


    matthew8 wrote: »
    Did you take into account that starting velocity was 2? That's where you would've gone wrong to get those. In fact I'm sure, because if you didn't your equation would have been t*2 -3t, which gives 0 and 3.

    Well, oops. I didn't think of that. Thanks, though :) How many marks would I lose, do you think?


  • Registered Users, Registered Users 2 Posts: 9,599 ✭✭✭matthew8


    Well, oops. I didn't think of that. Thanks, though :) How many marks would I lose, do you think?

    You'd definitely be down 3, and if they think it oversimplifies the question you'd be down 6 but I think that's a harsh interpretation.


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