HL maths question help

chatterboxxx95 · 03-01-2014 11:23am #1

Hey guys, trying to do maths papers, stuck on a particular q I'm wondering can anyone help me. Its Sec set A 2013 pilot paper 1 , question 8 (d) , about a raindrop falling and its speed , question is The raindrops falls vertically from a height of 620 m , how long does it take to reach the ground, I'll attach the formulas given as I'm too lazy to type them :pac:
Please if anyone knows how to do it I'd really appreciate help

yoho139 · 03-01-2014 12:53pm

That image is more than slightly illegible. Should really just be subbing into the formulas though, by the looks of it.

Ompala · 03-01-2014 2:23pm

s(t) = 6t + 0.3t^2 – 0.01t^3 0 ≤ t ≤ 10
and s(t) = k(t-10) t>10

First thing to do is find k. Find this through continuity of first derivatives at t=10.
Take the first derivatives to get
s'(t) = 6 + 0.6t -0.03t^2 0 ≤ t ≤ 10
s'(t) = k t>10

At t=10 the derivatives will have the same value, since the derivative here will represent the terminal velocity of the raindrop and it reaches terminal velocity at t =10.
So, 6 + 0.6(10) - 0.03(10)^2 = k which gives k = 9 (or k = 9m/s if you want to be really accurate)

Now we can write the equations of motion as
s(t) = 6t + 0.3t^2 – 0.01t^3 0 ≤ t ≤ 10
and s(t) = 9(t-10) t>10

Asked for time taken to fall 620m.
Find the distance it falls in the first 10s from 1st equation.
s(10) = 6(10) + 0.3(10)^2 - 0.01(10)^3 = 80m

It falls 80m in first 10s so that means it fall 620-80 = 540m in the time after 10s, so we use the 2nd equation to solve for the time
9(t-10) = 540
t-10=60
t=70s
Answer is 70s

yoho139 · 03-01-2014 2:35pm

Good eyes, and the reasoning is sound so far as I can tell.

chatterboxxx95 · 03-01-2014 6:15pm

Sorry for the illegible photo, the original was okay but I clicked into it and see what you mean! :pac: Thanks a mill, I just couldn't get my head around how to find k but I understand it now

chatterboxxx95 · 01-02-2014 4:54pm

Okay, bumping my own thread but how would you find the integral value for x if volume eq = 4x^3 -130x^2 +1000x amd you're told volume is 1512cm3 ? Its the educate ie papers, sample 2 paper 1question 7 part c

Ompala · 01-02-2014 5:01pm

chatterboxxx95 wrote: »

Okay, bumping my own thread but how would you find the integral value for x if volume eq = 4x^3 -130x^2 +1000x amd you're told volume is 1512cm3 ? Its the educate ie papers, sample 2 paper 1question 7 part c

Eh from how you describe it would you not just solve

4x^3 -130x^2 +1000x = 1512?

I don't see how integrals come into this, did you mean integer?

chatterboxxx95 · 01-02-2014 5:05pm

Ompala wrote: »

Eh from how you describe it would you not just solve

4x^3 -130x^2 +1000x = 1512?

I don't see how integrals come into this, did you mean integer?

Nope, papers definately say integral value! That's why I'm so confused by it! I tried just solving but not getting answer printed in the back :?

Ompala · 01-02-2014 5:10pm

chatterboxxx95 wrote: »

Nope, papers definately say integral value! That's why I'm so confused by it! I tried just solving but not getting answer printed in the back :?

Sounds like a mistake to me, cos there is an integer solution to

4x^3 -130x^2 +1000x = 1512 @ x = 2

The other solutions are x = 21.85 and x = 8.649

I don't have the exam papers myself, what answer they giving you?

chatterboxxx95 · 01-02-2014 5:18pm

Ompala wrote: »

Sounds like a mistake to me, cos there is an integer solution to

4x^3 -130x^2 +1000x = 1512 @ x = 2

The other solutions are x = 21.85 and x = 8.649

I don't have the exam papers myself, what answer they giving you?

I've put it away now but I think it was some dogey fraction, so possibly one of the non-integer roots, I think you're right though that it must be a must be a mistake! Im just gonna leave it solved as x=2 thanks for your help

EoghanIRL · 02-02-2014 12:41am

Differentiate s of t to get speed.
After 10 seconds it reaches terminal velocity . Find speed when t is 10 .
Time is distance divided by speed.
Distance is 620 divided by s. Speed I got as 9ms ^-1
620/9 = answer

Ompala · 02-02-2014 12:53pm

EoghanIRL wrote: »

Differentiate s of t to get speed.
After 10 seconds it reaches terminal velocity . Find speed when t is 10 .
Time is distance divided by speed.
Distance is 620 divided by s. Speed I got as 9ms ^-1
620/9 = answer

No, that wouldn't work, because you are assuming the object has constant velocity for the entire motion.

It doesn't, this is piece wise motion.

The answers are very similar though.

EoghanIRL · 02-02-2014 3:27pm

Ompala wrote: »

No, that wouldn't work, because you are assuming the object has constant velocity for the entire motion.

It doesn't, this is piece wise motion.

The answers are very similar though.

Yes youare right . I didn't have exam paper in front of me when answering.

Ompala · 02-02-2014 3:32pm

EoghanIRL wrote: »

Yes youare right . I didn't have exam paper in front of me when answering.

Jaysus I sounded awful cynical earlier, sorry lad! At least you understand the logic behind the stuff anyway.

HL maths question help

Comments