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Maths

  • 10-04-2012 03:12PM
    #1
    Registered Users, Registered Users 2 Posts: 11


    Has anyone got all the relevant formulas we have to learn that arent in the tables?

    Thanks


Comments

  • Registered Users, Registered Users 2 Posts: 25 paaula


    I know the ones for algebra since i have just been revising it.
    you have to know:
    x^3+y^3= (x+y)(x^2-xy+y^2)
    x^3-y^3= (x-y)(x^2+xy+y^)

    b^2-4ac>0 two real roots
    b^2-4ac=0 two equal roots
    b^2-4ac<0 no real roots

    α+β= -b/a (sum of two roots)
    αβ= c/a (product of two roots)

    how to make an equation: x^2- x(sum of roots) + (product of roots)

    α^2+β^2= (α+β)^2-2(αβ)
    α^3+β^3= (α+β)^3-3(αβ)(α+β)


  • Closed Accounts Posts: 3,479 ✭✭✭ChemHickey


    paaula wrote: »
    I know the ones for algebra since i have just been revising it.
    you have to know:
    x^3+y^3= (x+y)(x^2-xy+y^2)
    x^3-y^3= (x-y)(x^2+xy+y^)

    b^2-4ac>0 two real roots
    b^2-4ac=0 two equal roots
    b^2-4ac<0 no real roots

    α+β= -b/a (sum of two roots)
    αβ= c/a (product of two roots)

    how to make an equation: x^2- x(sum of roots) + (product of roots)

    α^2+β^2= (α+β)^2-2(αβ)
    α^3+β^3= (α+β)^3-3(αβ)(α+β)

    I use the same for the alpha ^ 3 one but you can use the same one as is for x ^3 +y^3 instead of learning two different ones! =)


  • Registered Users, Registered Users 2 Posts: 25 paaula


    Yeah, I think you can just learn one of them. After all they would both give you the exactly same result. Personally I would learn the alpha^3+beta^3 one since they ask you to find it sometimes in exam questions. :) But you can just use the x^3+y^3 as well, it would just take you longer to work it out if they ask you about the alpha and beta. :)


  • Registered Users, Registered Users 2 Posts: 11 ThatIrishGuy


    Brilliant :) greatly appreciated :) youre a lifesaver!


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