PHP countdown to 5 mins after current time?

py2006 · 13-01-2012 03:57PM #1

Hi guys,

I will like to insert a countdown timer of 5 mins after form has been submitted to a php page.

At the moment when they submit the form they see the date and time they submitted:

echo date("M d Y H:i", time()) ";

Any ideas?

seamus · 13-01-2012 04:06PM

I'm not really sure what you mean.

Do you want to display a timer to the end-user which counts down five minutes, or do you want to count down five minutes in the background (e.g. to prevent them submitting a form again for five minutes)?

py2006 · 13-01-2012 04:10PM

seamus wrote: »

I'm not really sure what you mean.

Do you want to display a timer to the end-user which counts down five minutes, or do you want to count down five minutes in the background (e.g. to prevent them submitting a form again for five minutes)?

The former!

So once the form is submitted, they are taken to the php page which displays what they have filled out and also a countdown starting at 5.00 and going down in secs to 0.

Is that possible?

seamus · 13-01-2012 04:12PM

Not in PHP, you'd be looking for a piece of simple javascript to do that. Google for a "countdown timer" or something like that, there will be literally thousands of code samples to download.

Webmonkey · 13-01-2012 04:13PM

py2006 wrote: »

The former!

So once the form is submitted, they are taken to the php page which displays what they have filled out and also a countdown starting at 5.00 and going down in secs to 0.

Is that possible?

What's the count down for?

I'd consider using javascript for that instead.

py2006 · 13-01-2012 04:17PM

Oh really? I didn't realise that. It doesn't serve any real purpose, just something to add.

I thought maybe it could be done in php as I am trying to learn it.

Webmonkey · 13-01-2012 04:18PM

py2006 wrote: »

Oh really? I didn't realise that. It doesn't serve any real purpose, just something to add.

I thought maybe it could be done in php as I am trying to learn it.

PHP is server side so once it's generated on the server and sent to the browser, PHP can't do anymore. It's up to the client then.

py2006 · 13-01-2012 04:38PM

Webmonkey wrote: »

PHP is server side so once it's generated on the server and sent to the browser, PHP can't do anymore. It's up to the client then.

Ah that makes sense.

Actually while I have your undivided attention. Can you think of any reason why the word Array appears when I get the results of a an array.

The array works itself no problem. It just has this extra word thrown in haha

Webmonkey · 13-01-2012 04:40PM

You are probably just printing the array. You can only print the elements of it.

[php]
echo print_r($myArray);
[/php]

That would show the contents of the array.

If you want to do it in a nice way you will have to iterate over the array elements and construct your own way of displaying the data using the elements of the array.

py2006 · 13-01-2012 04:50PM

Webmonkey wrote: »

You are probably just printing the array. You can only print the elements of it.

[php]
echo print_r($myArray);
[/php]

That would show the contents of the array.

If you want to do it in a nice way you will have to iterate over the array elements and construct your own way of displaying the data using the elements of the array.

Well the following is taking info from 2 checkboxes:

$pricelist_Books = "3.99";

if(isset($_POST['book']))
 
 {
	for ($i=0; $i<count($_POST['book']);$i++) {
		echo "<br />" . $_POST['book'][$i] . "<br /><br />". "<div id=\"prices\">" . "(". "&#8364;". $pricelist_Book . " " . "each" . ")" . "</div>" ."<br /><br />";
	}
 }
 
 $TotalBookPrice = count($_POST['book']) * $pricelist_Book ;
 echo "Total: " . "&#8364;" . number_format($TotalBookPrice, 2) . " <br /><br />";

It works fine except for the word ARRAY appearing. When neither checkbox is selected then it doesn't show up!

Creamy Goodness · 13-01-2012 09:47PM

use var_dump($var); to see what data type the variable is.

if it's printing out Array, it's an array and you'll need to go back and debug your code.

for example: $pricelist_Books = "3.99"; should be $pricelist_Books = 3.99; it's a floating point number and not a string, so when you do $TotalBookPrice = count($_POST) * $pricelist_Book ; you're multiplying a integer (the count) by a string value. not sure if this is your problem but it's not good practice.

PHP countdown to 5 mins after current time?

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