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Higher Maths Paper 2 tip[s]

  • 05-06-2003 7:53pm
    #1
    Closed Accounts Posts: 16,396 ✭✭✭✭


    paper 2..solid hint:

    alright...after a session tonight, turns out he cant remember much about the circles on the line question :(

    sorry about that BUT least it sorted out proving 3 points are collinear :)

    anway...

    for Section B-Q8.

    For those with the Mathematices Revision for LC Higher Level [paper2] - green book....

    it's the question on page 203.

    ambulance at the point a, has to reach point c on the road bc.

    It travels 80Km\Hr between a and any point on the road.

    Once on the road, it travels at 100Km\Hr.

    If |bc| = 9Km, |ba| = 3Km & |bp| = xKm,

    calculate value for x for which the time is a minimum and calculate this minimum time.



    exam%20example%20part%201.jpg
    exam%20example%20part%202.jpg


    Something similar is to appear as Q8 c

    *************
    Ratio Test possibly

    Difference Equations Theorem

    possible proof on Circle [eqn of tangent] or Line [angle between 2 lines OR perpendicular distance]


Comments

  • Closed Accounts Posts: 91 ✭✭DSMe


    damn thats a good tip , any ideas on what type of question it the rest would be ?
    Any thing else u think might come up?


  • Closed Accounts Posts: 14,013 ✭✭✭✭eirebhoy


    I've searched through the circle chapter of my book and I can't find this proof anywhere. How do you prove it?


  • Closed Accounts Posts: 78 ✭✭pfitz


    i think its:
    if the slope of the line joining the centres of the circles is the same then they are collinear?


  • Closed Accounts Posts: 402 ✭✭Man U babe


    Using the 3 centres as the 3 points of a triangle, show that the area of said triangle is 0.


  • Registered Users, Registered Users 2 Posts: 318 ✭✭Celtic Tiger


    Theres a third way: let points equal p,q and r and just show that |pq|+|qr|=|pr|


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  • Closed Accounts Posts: 278 ✭✭aine


    maybe this sounds silly...but its just an idea....how about ye get off the internet and actually get some sleep before ye're exam....usually works for me!

    but just so ye know, from someone who has done lc higher math....I'm pretty sure Celtic Tiger is right...would have to check book though...its been a while!


  • Registered Users, Registered Users 2 Posts: 318 ✭✭Celtic Tiger


    Bah sleep! Will catch up at the weekend. Easy day 2moz anyway :)


  • Registered Users, Registered Users 2 Posts: 20,617 ✭✭✭✭PHB


    Celtix tiger, you didnt prove that they were coliner there, you just proved that the distances were equal.


  • Registered Users, Registered Users 2 Posts: 318 ✭✭Celtic Tiger


    Yes but the distances are only going to be equal if points are all on the same line.


  • Registered Users, Registered Users 2 Posts: 20,617 ✭✭✭✭PHB


    Nevermind you're right


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  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    three circles have their centres on a line. Prove the centres are collinear

    Em.. I dont know about you guys, but when I see that I read.. "three circles have their centres on a line. Prove they have their centres on a line."


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    Or more appropriately "three points are collinear, prove they're collinear"


  • Closed Accounts Posts: 91 ✭✭DSMe


    i read this the same as sev.... and if its a straight line where does the triangle come from?


  • Registered Users, Registered Users 2 Posts: 2,563 ✭✭✭sikes


    it will not be worded as that, in fact if they are really gay and annoying they will say something like this

    What do you notice about the centre of circles A, B, C?


  • Registered Users, Registered Users 2 Posts: 318 ✭✭Celtic Tiger


    If you are unsure what collinear means check the bottom of this page


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    I cant see that ever being a question, it just sounds stupid. Its tantamount to saying "Triangle abc is a triangle. Prove it's a triangle"


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    The only manifestation of such a question I can imagine, is if you were given the equation of three separate circles. And then asked to show that the centers of them are collinear. Or perhaps told that a particular line is a tangent to 3 identical circles, and asked to prove the centers or collinear. Something like that maybe, something that actually makes sense.


  • Closed Accounts Posts: 78 ✭✭pfitz


    so how exactly do you prove that three points are collinear?


  • Registered Users, Registered Users 2 Posts: 20,617 ✭✭✭✭PHB


    You prove they are on a straight line basically by one of the following methods :

    if the slope of the line joining the centres of the circles is the same then they are collinear

    Using the 3 centres as the 3 points of a triangle, show that the area of said triangle is 0.

    let points equal p,q and r and just show that |pq|+|qr|=|pr|

    Go DSme, Man U Babe, and Celtic Tiger


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    alright alright...my english may not be great :P

    I'll find out for defo tonight n post up again.

    original post was off the top of my head from Wednesday night


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  • Registered Users, Registered Users 2 Posts: 2,563 ✭✭✭sikes


    Kaimera

    was your original message coded cos you said something is to be left out of above equation or something like that.

    btw i am not taking the piss.

    good luck on monday. Any other tips? i reckon proving cos rule


  • Closed Accounts Posts: 78 ✭✭pfitz


    could u get the equation of the line between two of the points and then substite the third point in to the equation to see if it is on the line


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    original post edited slash updated :)


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    Where the hell you get your |bp| from in that question?


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    Right.. I take it p is the point where the car meets the road. Hmmm... you sure theres not a little more information to go with that question? Cos I can see where its coming from, but it doesnt seem to work without having an angle between [ba] and [ac]. Havn't put a lot of thought into this yet tho. But is that all exactly quoted from the book? With no pictures?


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    I'll scan in the page 2m morning.
    too late now to be arsing around with a scanner atm.

    a,b,p make a right angled triangle

    |ab|=3
    |bp| = x
    |ap| = sq root 9+x2

    |pc| = (9-x)

    Time = Distance/Speed

    T = |ap|/80 + |pc|/100

    working T out...(9+x2)^1/2/80 + 9/100 - X/100

    Use Chain Rule to find dT/dX

    Get T

    T = D/S


  • Registered Users, Registered Users 2 Posts: 318 ✭✭Celtic Tiger


    Thanks for sharing the tip Kaimera :)


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    Yeh thats how you do it.

    It's simple then, just differentiate. Find the value of x when dT/dx is 0. Then throw that value of x into your equation for T.

    Of course not knowing that abp formed a right triangle, meant that I had a very nasty looking expression for the final x value, in terms of cos(angle abp) which had to be found using the cosine rule on the triangle abp. It made it a more interesting question tho.


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    there is a diagram with the question so should be one on the paper.

    just fill in the values.

    this question isn't in the Maths book I've been using and I'm not sure if it's only in revision books.

    Never been asked on a paper iirc.

    they seem to be moving away from volume etc on Q8


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  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    If you have any more.. keep em coming, if I cant drag myself away from the pc to actually do some study myself, then I'll get it done on the pc. Thanks for the tip.


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    aside from the first post..

    difference eqns theorem

    Ratio test

    had my last session of grinds tonight. He's packed out 2m with guys!

    He was right about recurring decimals and Vol of sphere by integration and possible induction proof [albeit prove y=x^n dy/dx = nx^n-1] on paper 1.

    He'd be on some money up in Dublin in one of the private institutes :)


  • Posts: 2,874 ✭✭✭ [Deleted User]


    Kameira ya posting up that page netime soon plz? :)


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    oops! :eek:!

    I knew I forgot something when I was scanning that exam paper this morning.

    Have it up asap tay-o.


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    pixels posted in first post :)


  • Closed Accounts Posts: 11 Shelliestar


    OK my maths grind teacher said that he had a feeling about the cosine rule, proof i think i but fear trig like the plague so i wasn listening too well.
    He also said the proof of

    Sin2A =
    2TanA
    1 + Tan2A

    and

    Tan A =
    ±m1 - m2
    1 + m1m2

    were very likely, he said he knew the two people that set the paper and had been talking to one of them last week.
    Anyways hope that was helpful


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  • Registered Users, Registered Users 2 Posts: 2,835 ✭✭✭StickyMcGinty


    is that sin2a stuff not in the log book?


  • Registered Users, Registered Users 2 Posts: 1,328 ✭✭✭Sev


    Looking over the papers, I noticed there is a distanct lack of them lamda questions in the past 8 years. The types where you need the equation of a specific line that passes through the point of intersection of two other lines, L + M.

    Then that line becomes, (lamda)L + M = 0

    Only one question like that, and its a part (a) on 1995. Theres also a lack of circle and line proofs since 1997.


  • Closed Accounts Posts: 16,396 ✭✭✭✭kaimera


    Best of luck tomorrow peeps :)

    I'm gone from Boards for the night.

    /me hopes for a nice paper 2


  • Registered Users, Registered Users 2 Posts: 895 ✭✭✭imp


    I think maybe I should start revising now.

    }:>


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