Python

whats newxt

How do i get the following code to work? Basically i'm trying to take list (array) values and save them as an int, for example i want element [0] to save it's raw_input value into a int.

Here the code snippet:

a = 0

myList=[1,2,3,4,5,6]
a = raw_input()
a = mylist[0]
print (a)

At the moment it gives me errors. Any clue ? only started learning python yesterday.

whats newxt

It print the list length but not the value.

deconduo

whats newxt wrote: »

How do i get the following code to work? Basically i'm trying to take list (array) values and save them as an int, for example i want element [0] to save it's raw_input value into a int.

Here the code snippet:

a = 0

myList=[1,2,3,4,5,6]
a = raw_input()
a = mylist[0]
print (a)

At the moment it gives me errors. Any clue ? only started learning python yesterday.

Currently this is what your code does:

a = 0
# Sets 'a' to 0

myList=[1,2,3,4,5,6]
# Creates an array myList that contains the numbers 1 to 6

a = raw_input()
# Sets 'a' to the input from the console 

a = mylist[0]

# Sets 'a' to the first element in mylist.
# This will fail as the array you defined earlier is myList not mylist.

print (a)
# Prints 'a'

Apart from missing the capital L in myList, you change the value of 'a' 3 times. So the first 2 times you set it do nothing, as it gets over-written each time.

What exactly do you expect the raw_input() function to do?

whats newxt

deconduo wrote: »

Currently this is what your code does:

a = 0
# Sets 'a' to 0

myList=[1,2,3,4,5,6]
# Creates an array myList that contains the numbers 1 to 6

a = raw_input()
# Sets 'a' to the input from the console 

a = mylist[0]

# Sets 'a' to the first element in mylist.
# This will fail as the array you defined earlier is myList not mylist.

print (a)
# Prints 'a'

Apart from missing the capital L in myList, you change the value of 'a' 3 times. So the first 2 times you set it do nothing, as it gets over-written each time.

What exactly do you expect the raw_input() function to do?

Take user input and save the value in mylist[0] then take mylist[0] and save it value as an int and call the variable b or something. Then print b to the console.

whats newxt

I got it to print out the array index but not the value it holds?

whats newxt

It's ok i got the whole thing to work:

a = 10#declares a
b = 5#decalres b
i = 0
z = 0
y = 0



if a < b:#if argument true
    print "True"#then do this
else:#otherwise
    print "false"#do this

input = raw_input()#takes user input
print "Your name is: " + input#prints to console + input

for x in range(0, 3):#for loop X4
    i += 1#increment i by one each loop

print "----------"#print to console
print (i)#print value of i

z = i*b#basic math
print (z)#print to console

mylist=[1,2,3,4,5,6]
y = mylist[0]
y = raw_input()
print "_________"
print (y)
print "_________"

whats newxt

Python is amazing.

deconduo

whats newxt wrote: »

Take user input and save the value in mylist[0] then take mylist[0] and save it value as an int and call the variable b or something.

That's a bit of a strange way of doing things. Is there a particular reason you are doing it that way?

If that's what you want:

myList = [1,2,3,4,5,6]
# Creates a list with the numbers 1 to 6

a = raw_input('Enter your value: ')
# Sets a equal to the console value

myList[0] = a
# Replaces the first element in myList with a

b = int(myList[0])
# Sets b equal to the int value of the first element in myList.

So for example, if you give an input of 9, you will have:

a = '9'
myList =
b = 9

This will fail if the input given can't be parsed to an int.

EDIT: Ah I see you figured it out yourself.