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a simple brain teaser

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  • 19-04-2013 8:11pm
    #1
    keithsfleet
    Registered Users Posts: 1,072 ✭✭✭


    Use each number once and once only..
    Each number must be used.

    2, 3, 4, 5 = 28 how?

    Don't post the answer if you get it.
    Pm me if you want it


«13

Comments

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    #2
    Micky Dolenz
    Registered Users Posts: 44,080 ✭✭✭✭Micky Dolenz


    Easy peesy.


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    #3
    shopaholic01
    Closed Accounts Posts: 4,916 ✭✭✭shopaholic01


    keithsfleet wrote: »
    Use each number once and once only..
    Each number must be used.

    2, 3, 4, 5 = 28 how?

    Don't post the answer if you get it.
    Pm me if you want it
    You've just killed your own thread!


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    #4
    the keen edge
    Closed Accounts Posts: 1,533 ✭✭✭the keen edge


    shopaholic01 wrote: »
    You've just killed your own thread!

    Ah stop, sure there is so much to discuss.


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    #5
    keithsfleet
    Registered Users Posts: 1,072 ✭✭✭keithsfleet


    shopaholic01 wrote: »
    You've just killed your own thread!


    Ha yea sorry a few pre pub drinks in me.
    The head ain't the clearest.
    Ok people, fire away if you want to answer it.


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    #6
    EDDIE WATERS
    Registered Users Posts: 853 ✭✭✭EDDIE WATERS


    two cubed+4 times 5 =28


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    #7
    NuckingFacker
    Closed Accounts Posts: 5,221 ✭✭✭NuckingFacker


    I never was much good at maths...brain hurts...


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    #8
    Ficheall
    Registered Users Posts: 9,018 ✭✭✭Ficheall


    People answering will still kill the thread.

    There are multiple solutions - perhaps you could define what operations you're suggesting people use?


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    #9
    Ficheall
    Registered Users Posts: 9,018 ✭✭✭Ficheall


    EDDIE WATERS wrote: »
    3²+4 times 5 =28

    WRONG! :P


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    #10
    artanevilla
    Moderators, Education Moderators, Sports Moderators Posts: 10,264 Mod ✭✭✭✭artanevilla


    keithsfleet wrote: »
    Use each number once and once only..
    Each number must be used.

    2, 3, 4, 5 = 28 how?

    Don't post the answer if you get it.
    Pm me if you want it

    nAK9tSW.jpg


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    #11
    13spanner
    Closed Accounts Posts: 1,006 ✭✭✭13spanner


    (4 x 5) + 2 cubed (which would be a lil' 3) = 28.


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    #12
    keithsfleet
    Registered Users Posts: 1,072 ✭✭✭keithsfleet


    It's incredibly simple.
    You don't need to Square anything.

    Purely use addition multiplication and subtraction.


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    #13
    sock puppet
    Registered Users Posts: 4,586 ✭✭✭sock puppet


    Is this from the Special Olympics version of Countdown?


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    #14
    tritium
    Registered Users Posts: 7,421 ✭✭✭tritium


    EDDIE WATERS wrote: »
    3²+4 times 5 =28

    I think you mean two cubed rather than three squared


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    #15
    Skid X
    Registered Users Posts: 21,444 ✭✭✭✭Skid X


    keithsfleet wrote: »
    Use each number once and once only..
    Each number must be used.

    2, 3, 4, 5 = 28 how?

    Don't post the answer if you get it.
    Pm me if you want it

    ((2*5)-3)*4 = 28


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    #16
    keithsfleet
    Registered Users Posts: 1,072 ✭✭✭keithsfleet


    Skid X wrote: »
    ((2*5)-3)*4 = 28

    Congrats you got it


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    #17
    Nailz
    Registered Users Posts: 7,688 ✭✭✭Nailz


    Ficheall wrote: »
    People answering will still kill the thread.

    There are multiple solutions - perhaps you could define what operations you're suggesting people use?
    This has become unfair just by you being here. :P


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    #18
    humbert
    Registered Users Posts: 5,238 ✭✭✭humbert


    No cubing required.


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    #19
    not yet
    Registered Users Posts: 7,008 ✭✭✭not yet


    I don't know what a tracker mortgage is...


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    #20
    tritium
    Registered Users Posts: 7,421 ✭✭✭tritium


    humbert wrote: »
    No cubing required.

    But a perfectly valid (and slightly flashy :) ) approach


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    #21
    [Deleted User]
    Posts: 0 ✭ [Deleted User]


    not yet wrote: »
    I don't know what a tracker mortgage is...
    Well, that sums up this thread!


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    #22
    kraggy
    Closed Accounts Posts: 6,414 ✭✭✭kraggy


    Take the diagonal part of the number 4 away and it becomes a plus sign.

    Then you don't even have to change the order of the numbers or do anything else and it's right.

    2 3 + 5 = 28


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    #23
    coffee_cake
    Moderators, Category Moderators, Politics Moderators, Recreation & Hobbies Moderators, Society & Culture Moderators Posts: 81,310 CMod ✭✭✭✭coffee_cake


    I love countdown


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    #24
    Ficheall
    Registered Users Posts: 9,018 ✭✭✭Ficheall


    bluewolf wrote: »
    I love countdown

    We need a Rachel.


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    #25
    Lawrence1895
    Registered Users Posts: 7,627 ✭✭✭Lawrence1895


    Can I send a PM, that I hate maths? :D


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    #26
    shopaholic01
    Closed Accounts Posts: 4,916 ✭✭✭shopaholic01


    Ficheall wrote: »
    We need a Rachel.
    And a few consonants and vowels.


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    #27
    coffee_cake
    Moderators, Category Moderators, Politics Moderators, Recreation & Hobbies Moderators, Society & Culture Moderators Posts: 81,310 CMod ✭✭✭✭coffee_cake


    Ficheall wrote: »
    We need a Rachel.

    Hasn't been the same since whiteley and vorderman!


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    #28
    kraggy
    Closed Accounts Posts: 6,414 ✭✭✭kraggy


    Here's one while we're at it.

    You have

    a. A weighing balance
    b. 9 balls

    8 of the balls are the same weight, one is heavier than the others.

    Question: What is the least number of times you can think of using the weighing balance to determine which ball is of a heavier weight?


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    #29
    Ficheall
    Registered Users Posts: 9,018 ✭✭✭Ficheall


    bluewolf wrote: »
    Hasn't been the same since whiteley and vorderman!

    Rachel and Susie are still there and that's good enough for me.


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    #30
    Chuck Stone
    Closed Accounts Posts: 13,030 ✭✭✭✭Chuck Stone


    2 pears + 3 apples + 2 peaches

    =
    A fruit salad


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    #31
    coffee_cake
    Moderators, Category Moderators, Politics Moderators, Recreation & Hobbies Moderators, Society & Culture Moderators Posts: 81,310 CMod ✭✭✭✭coffee_cake


    kraggy wrote: »
    Here's one while we're at it.

    You have

    a. A weighing balance
    b. 9 balls

    8 of the balls are the same weight, one is a different weight.

    Question: What is the least number of times using the weighing balance necessary to determine which ball is of a different weight?

    (Who can write the question in better English than that please?)

    I originally thought 5, but you can probably group them together and do it fewer times
    2 or 3


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