Free MIT online qualification...

smcgiff

Only one course for now, but more to follow...

https://6002x.mitx.mit.edu/


Who says you need $50k a year for MIT

smcgiff

I've signed up for this course.

Hopefully others will as well and we can discuss the course here. I've Leaving Cert physics, but that's a bit rusty, as is the algebra.

Hopefully we can work through it together here.

corazon

I've been on their email list for a while and also signed up for the course. Math skills are a little rusty so should be interesting.

WarbossPepe

anybody have any idea what they mean by "more advanced mathematics coming up in the second semester"?

Tigger

enrolled

i've done 1st year electronic engineering (17 years ago)
and i've an applied science diploma so I hope to contribute here

Tigger

btw
whoot im in MIT \m/(-.-)\m/

strandsman

did anyone start MITx yet?

corazon

Had a look at the course material yesterday. Fairly intensive for someone like me who has been out of school for a long time but plan to give it my best shot. First homework is due on the 16th.

smcgiff

corazon wrote: »

Had a look at the course material yesterday. Fairly intensive for someone like me who has been out of school for a long time but plan to give it my best shot. First homework is due on the 16th.

There's homework :eek:

I'm impressed.

It'll be the weekend before I get a chanct to look at it.

Hopefully others will post up their progresss here

brimal

I've enrolled in this course and am impressed with it so far.

Seems like MIT have put a lot of work into this.

I will be posting on this thread as I go along. Currently going through Week 1 lectures.

Tigger

week 1 done

brimal

You handed in your homework yet?

Tigger

i think so i hit check got all greens so i think thats handed in
i've had a look at week 2 and its not too steep a learning curve

strandsman

i'm stuck on the last question about the heaters that were incorrectly fitted, can get answer, Help!!!

brimal

Due date has been pushed back to the 18th now for Week 1 homework

Tigger

strandsman wrote: »

i'm stuck on the last question about the heaters that were incorrectly fitted, can get answer, Help!!!

work out the resistance of a heater
then use kirchoffs laws to work the total resistance in the circut

thedodger

Hi guys, I've just signed up for the course.
Did anyone join up late after missing a week or two?
Going to go through the first few weeks of the notes.
I'm very rusty on physics and maths too, how are you finding it?

Tigger

The first deadlines are tomorrow so you should be fine donno what will happen once they pass

thedodger

Tigger wrote: »

The first deadlines are tomorrow so you should be fine donno what will happen once they pass

looks like you can disregard the 2 lowest scores so should be fine after Ive caught up. Been having a look through the OCW stuff, great resource. glad i found out about this here, thanks a lot

strandsman

Tigger wrote: »

work out the resistance of a heater
then use kirchoffs laws to work the total resistance in the circut

OK, finally have wk 1 done, Thanks for the tip Tigger, but it still took alot of time to figure out, getting worried about what's ahead!!!, Have you done wk2?

Tigger

No
It's just gonna be rows of equations that need solving
Won't be hard just need accuracy and method

strandsman

I'm beat on H2P1: VOLTAGE-DIVIDER DESIGN, spent hours today at it, Can someone help?

Tigger

strandsman wrote: »

I'm beat on H2P1: VOLTAGE-DIVIDER DESIGN, spent hours today at it, Can someone help?

Voltage dividers use a sub circuit with resistors of a certain ratio to step down a voltage by that ratio

You need to make the voltage 1.5v
So a ratio of 3:1 will work

6/4*1=1.5
6/4*3=4.5

So you split the voltage 1.5 : 4.5

Or 3:1
http://en.m.wikipedia.org/wiki/Voltage_divider

Tigger

Once you have done that you need to make an apternatitive path for the current if the bulb is removed

So make a parallel circuit with the right voltage

brimal

Sorry guys I been mad busy, just finishing this Week 1 homework now.

BTW, I mentioned here due date is 18th - that's what it said on MITx site. But now they have changed it to this

Due to student feedback in the forums, we have changed due dates from the beginning of the weekend to the end of the weekend. Enjoy the extra time to complete assignments!

..which is I'm presuming, Monday the 19th. Must have been typo on the site.

EDIT: Checked the MITx forums, it's 23:59pm Sunday 18th in your own time zone.

strandsman

Tigger wrote: »

Voltage dividers use a sub circuit with resistors of a certain ratio to step down a voltage by that ratio

You need to make the voltage 1.5v
So a ratio of 3:1 will work

6/4*1=1.5
6/4*3=4.5

So you split the voltage 1.5 : 4.5

Or 3:1
http://en.m.wikipedia.org/wiki/Voltage_divider

I must be doing somthing wrong somewhere, My Vin 40, Vout 14, cant figure out the ohms and Vmax Vmin

Tigger

strandsman wrote: »

I must be doing somthing wrong somewhere, My Vin 40, Vout 14, cant figure out the ohms and Vmax Vmin

Post a screen shot of the circuit

strandsman

The resistances of commercially-available discrete resistors are restricted to particular sets. For example, the available values of resistors with 10% tolerance are selections from the E12 set multiplied by a power of ten from 10^0 through 10^5. The E12 set is
E12={10, 12, 15, 18, 22, 27, 33, 39, 47, 56, 68, 82}
Thus, you can buy 10% resistors with a nominal resistance of 330Ω or 33kΩ, but not 350Ω.
The "tolerance" means that if you buy a 10% 390Ω resistor you can be sure that its resistance is between 351Ω and 429Ω.
In this problem we need to choose 10% resistors to make a voltage divider that meets a given specification.


We are given an input voltage Vin=40.0V, and we need to provide an open-circuit output voltage of Vout≈14.0V. An additional requirement is that the Thevenin resistance as seen from the output terminals is between 10kΩ and 30kΩ. Assume first that the resistors have their nominal resistance. Come up with resistors R1 and R2 such that the division ratio Vout/Vin is within 10% of the requirement.
Of course, the resistances you chose are just nominal. Given that they are only guaranteed to have resistances within 10% of the nominal value, what is the largest and smallest value that Vout may have?

Dean820

Just signed up for this. So will MIT actually send a cert in the post if we complete this? How does it work?

strandsman

you have started late so you will have missed the first two weeks dead lines

Dean820

strandsman wrote: »

you have started late so you will have missed the first two weeks dead lines

Is it pointless doing it then? Can I just start late and do the first two weeks anyway?

strandsman

not sure if you can do the first two weeks as there is a dead line every week, I think they take out the lowest scoring two weeks to give an overall result at the end so maybe this would work for you. Have a crack at it anyway let me know how your doing.

hibby

I just finished 6002x. Anyone else make it to the finish line?

strandsman

no, gave up weeks ago, what score did you get?

hibby

strandsman wrote: »

no, gave up weeks ago, what score did you get?

100%.

It was hard work but I learned a lot!

Moonbeam

Well done
I missed the 1st week because I had not realised that it started,then just did not have the time.

jus_tin4

wish i seen this tread months ago....anyone know if they are doing it again?

Mmmm_Lemony

jus_tin4 wrote: »

wish i seen this tread months ago....anyone know if they are doing it again?

www.udacity.com
www.coursera.com

MOOC's very popular at the moment.

hibby

jus_tin4 wrote: »

wish i seen this tread months ago....anyone know if they are doing it again?

Yes, as far as I know they will run 6002x again in "the fall" along with some additional courses.

KERSPLAT!

Sorry to drag up an old thread but how did ye sign up yo MITX for free?

http://www.mitx.org/membership/student.aspx

The above link says you have to be a student in New England, any other option has fees

HigsBoson

You have to sign up via the EdX Platform.

https://www.edx.org/

KERSPLAT!

HigsBoson wrote: »

You have to sign up via the EdX Platform.

https://www.edx.org/

Brilliant, thank you