Need help to code these with java!!!

jayvenom

Am learning how to use this language and 've been given these problems to do. thing is, i just started this last week, and have barely got past loops. Help, anyone???
1)A Pythagorean triplet is a set of three natural numbers, a < b < c, for which a2 + b2 = c2
For example, 32 + 42 = 9 + 16 = 25 = 52.
There exists exactly one Pythagorean triplet for which a + b + c = 1000. Your output should
look like this (of course with the right numbers, 10, 20 and 30 are obviously not a valid
solution)
The Solution is a=10, b=20, c=30.
2)The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 55^2 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and
the square of the sum is 3025 - 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural
numbers and the square of the sum. Your output should look like this. (Replace 10, 20 and
30 with your right answer!):
Sum of squares = 10
Square of sum = 20
The Square of sum - Sum of squares is 30.

And finally.....
3)The Game of Pig is a dice game with simple rules:
• There are two players, they play with one die
• The goal of the game is to reach 100 points
• Each turn a player rolls the die until he rolls a 1 (called a pig), until he
holds or until he reaches the 100 point mark.
• Whenever a player rolled the die and did not roll a 1 he continues. He is
now faced with two choices:
• roll again: If he rolls anything between 2 and 6 the the number is added
to the playerʼs turn total. If he rolls a 1 then the playerʼs turn total is
erased and it is the opponentʼs turn
• hold: The turn total is added to the playerʼs score and it is the
opponentʼs turn

a)Implement the Game of Pig for two human players playing on the same machine. You
need to ask the player if he wants to hold or roll after each dice roll. Also you should
provide information to whose turn it is and the current score.
(Hint: Use nextLine() if you want to have a String, use nextInt() if you want to have an int).

b)Implement the Game of Pig for one human player. He should have an opponent that is
played by the computer. Use code comments to relate the strategy behind your computer
player.
(Hint: Your computer player should make the decisions roll or hold based upon the turn
total, the score of the human player and/or the score of the computer player.

Have less than 8 hrs to do this..............

Fremen

We're not really here to do your work for you. If there's something you don't understand, try to articulate what it is that's bugging you, and people will try to help out.

To be honest, I doubt you'll get much sympathy- it looks like you've left everything until the very last minute. Not really the best way to approach an assignment.

the_monkey

unfortunately have to agree , why not post some of the code you have allready attempted and then ask for some pointers...

jayvenom

okay

jayvenom

for the 4th one:

public class PythagoreanTriplet
{

public static void main(String[] args)
{

final int MAXIMUMNUMBER=1000;
int number1,number2,number3;

System.out.println("Program to determine the Pythagorean Triplet for which a + b + c =1000");
System.out.println("

---

");
System.out.println(" ");

for(int i=1;i<=500;i++)
{

for(int j=1;j<=500;j++)
{

for(int x=1;x<=500;x++)
{
number1= i * i;
number2 = j * j;
number3= x * x;


if(((number1 + number2)==number3) && ((i + j + x)==MAXIMUMNUMBER))
{
System.out.println("The solution is " + "a=" + i + " ," + "b=" + j + "," + "c="+ x);
System.exit(0);
}

}

}

}




}

}

jayvenom

what do y'all think?

28064212

jayvenom wrote: »

what do y'all think?

That works, doesn't it? Are you looking for coding style criticisms or what?

Fremen

He's running three nested loops 500 times each, which means 125,000,000 operations. Maybe it's too slow?
Again, OP, we need more input from you than just a code snippet. If you want help, you need to be specific.


You have two conditions

[latex]x+y+z = 1000[/latex]

and

[latex]x^2 + y^2 = z^2[/latex]

which is the same as

[latex] z = \sqrt{x^2 + y^2} [/latex]

If you substitute that into the first equation, you have a relation in X and Y for which you want integer solutions. You should be able to loop through all the possibilities much faster.

jayvenom

ok that works.

jayvenom

i still cant figure out how to begin coding the first one, tho.

jayvenom

i mean the third one

Fremen

The pig question is really more programming than maths. It's the kind of thing that's covered in a standard java textbook. Just break it down into different cases. Who's turn is it? Prompt them to enter a command to hold or roll again. How do you generate a random dice roll? What was their roll? if the roll was 1, what happens? etc...
You might want to use a "while" loop and use a boolean "gameisover" as a loop guard. How do you decide if a game is over?

The game is probably simple enough that there's an optimal way for a computer to play. You need to think about that a bit and post your ideas here though.

jayvenom

ok, so this is what i did for the game of pig.
comments???

import java.util.*;
/**
* @author Joshua-Derek Bossman-Adotevi
*/
public class GameofPig {
public static void main(String[] args) {
Scanner diceThrow = new Scanner(System.in);
//initializing players and scores
int player1 = 1;
int player2 = 2;
int player = 1;

int player1turn; // score for one roll of the dice for fisrt player
int player1turnTotal = 0; // score for one round of play for first player
int player1totalScore = 0; //overall score for first player
int player2turn; // score for one roll of the dice for second player
int player2turnTotal = 0; // score for one round of play for second player
int player2totalScore = 0; //overall score for second player

//For first player's turn
System.out.println("This is a game of pig. Two players roll a dice until one");
System.out.println("players score reaches 100. That player then wins the game.");
System.out.println("The game begins with player One.");
System.out.println("

---

");
System.out.println("");

while(player1totalScore < 100 && player2totalScore < 100){
if(player == 1){
System.out.println("Player 1, press 'p' to play or 'h' to hold: ");
String choice = diceThrow.nextLine();

if(choice.equals("p")){
player1turn = (int)(Math.random()*6+1);
System.out.println("Your dice throw is: " + player1turn);

if(player1turn != 1){
player1turnTotal = player1turnTotal + player1turn;
System.out.println("Your turn total is:" + player1turnTotal);
System.out.println("

---

");
}
else {
System.out.println("PIG!!!");
System.out.println("Your score for this round is set to 0. Player 2 plays next.");
System.out.println("

---

");
// switching players if the first player plays a 1
player1turnTotal = 0;
player = 2;
player1 = 2;
player2 = 1;
}

}
else if(choice.equals("h")){
player1totalScore = player1totalScore + player1turnTotal;
// switching players if the first player holds
player = 2;
player1 = 2;
player2 = 1;
}

}
/*
This is for the second players turn
*/
if(player == 2){
System.out.println("Player 2, press 'p' to play or 'h' to hold: ");
String choice = diceThrow.nextLine();

if(choice.equals("p")){
player2turn = (int)(Math.random()*6+1);
System.out.println("Your dice throw is: " + player2turn);

if(player2turn != 1){
player2turnTotal = player2turnTotal + player2turn;
System.out.println("Your turn total is:" + player2turnTotal);
System.out.println("

---

");
}
else {
System.out.println("PIG!!!");
System.out.println("Your score for this round is set to 0. Player 1 plays next.");
System.out.println("

---

");
// switching players if the second player plays a 1
player2turnTotal = 0;
player = 1;
player1 = 1;
player2 = 2;
}
}
else if(choice.equals("h")){
player2totalScore = player2totalScore + player2turnTotal;
// switching players if the second player holds
player = 1;
player1 = 1;
player2 = 2;
}

}
}
System.out.println("Player 1 total score is: " + player1totalScore);
System.out.println("Player 2 total score is: " + player2totalScore);
if(player1totalScore > player2totalScore){
System.out.println("PLAYER 1 WINS!!!!!!");
}
else{
System.out.println("PLAYER 2 WINS!!!!!!");
}
}

}

jayvenom

i knew this was not complete. tested it out and it worked up to a point. but the counters were not reset when a player gave up his his turn. this made the game end faster and nullified the purpose, i think. Thanks for the help, guys.