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Subnetting

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Comments

  • #32
    mcdonagh521
    Closed Accounts Posts: 9 ✭mcdonagh521


    Thanks!


  • #33
    OwenM
    Registered Users, Registered Users 2 Posts: 860 ✭✭✭OwenM


    Why won't subnetting be used with ipv6 ?

    Just curious.


  • #34
    rmacm
    Closed Accounts Posts: 2,039 ✭✭✭rmacm


    OwenM wrote: »
    Why won't subnetting be used with ipv6 ?

    Just curious.

    Eh what gave you that idea?


  • #35
    Moriarty
    Registered Users, Registered Users 2 Posts: 6,007 ✭✭✭Moriarty


    I didn't know this was now the homework forum :)


  • #36
    accensi0n
    Registered Users, Registered Users 2 Posts: 3,015 ✭✭✭accensi0n


    OwenM wrote: »
    Why won't subnetting be used with ipv6 ?

    Just curious.

    Subnetting is used with IPv6...


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  • #37
    Nalced_irl
    Closed Accounts Posts: 1,715 ✭✭✭Nalced_irl


    dellas1979 wrote: »
    192.64.10.0/28, how many subnets and hosts can be calcluated

    OK. I worked it out as:

    n n h h
    192.64.10.0

    Gone into the last octet to get your 4 bits = 2 to power 4 - 2 = 14 subnets

    4 bits left = 2 to power 4 - 2 = 14

    14 subnets, 14 hosts.

    Am I correct? Any more I can practice on?

    I have the bloody Net+ exam tomorrow and this is a tough subject to get your head around. The 2 squared -2 approach to me anyway is the easiest to use. Tried other ways to see if it made it easier to work out how many hosts/subnets they could handle but always come back to this as the easiest to use.


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