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Quick math leverage question.

  • 10-09-2020 1:17pm
    #1
    corkgsxr
    Registered Users, Registered Users 2 Posts: 3,404 ✭✭✭


    411g at 550mm from a pivot.

    How much does that effectively weigh.

    As effective weight increases with distance from a point.


Comments

  • #2
    Michael Collins
    Moderators, Science, Health & Environment Moderators Posts: 1,851 Mod ✭✭✭✭Michael Collins


    To be clear, the weight depends on the mass and the acceleration due to gravity gv = 9.81 m/s^2, so clearly this won't change -- you obviously know this as you use the phrase 'effective weight', but this isn't actually a scientific quantity, or at least not not a widely used one.

    I would guess torque would be the closest to what you're looking for, torque being a term for a turning force (which in this case acts to turn the lever around the pivot -- assuming there's a straight lever arm from a fixed pivot to the 411g mass).

    In this case, converting everything to the mks unit system (metres, kilograms, seconds) the torque would be

    t = rF = (0.55)(0.411*gv) = (0.55 m)(0.411 kg*9.81 m/s^2) = 2.22 N m

    where gv = 9.81 m/s^2, and, in case you're trying to figure out the dimensions of the answer (N m = newton-metres), 1 N = 1 kg * 1 m/s^2.


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