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non-quake (physics)

Vincent · 1999-11-09 19:02:00

A ball is thrown vertically upwards from ground level with an initial speed of 20m/s what is the hightest height reached? Can someone please explain how to do this, i dont want the answer on it's own, (i wasn't in when we were doin this)

09-11-1999 08:02PM

#1

Vincent

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Posts: 510

A ball is thrown vertically upwards from ground level with an initial speed of 20m/s

what is the hightest height reached?

Can someone please explain how to do this, i dont want the answer on it's own,

(i wasn't in when we were doin this)

0

Comments

#2 09-11-1999 09:44PM

El_Presidente

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Posts: 1346

k , its like this...
u = initial velocity
v = final velocity
a = aceleration
S = Distance

v(squared) = u(squared) + 2AS

u = 20
v = 0
a = -9.8
t dosent matter
S is what your looking for.

0*0 = 20*20 + 2(-9. (S)
-400 = -19.6(S)

S= 20.0408 meters

I think ( but its been a while since i'v done one of those)

El

0
#3 09-11-1999 09:45PM

El_Presidente

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er, ok, where the smily thing is there should be an eight, so thats -9.8

0
#4 09-11-1999 10:00PM

Vincent

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thanks El_Presidente, much obliged

0