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Half Wave rectifier question

Comments

  • #2
    BrianDug
    Registered Users, Registered Users 2 Posts: 163 ✭✭BrianDug


    I give it a shot as:

    230 V * 1/5 = 46Vrms on the secondary

    Output pk voltage will be 46 * sqrt(2)/pi = 20.70V = DC component = Average value of HWR voltage
     --> should be output pk = 46 * sqrt(2) = 65V as you have it, and the Dc component is then pk/pi = 65/pi = 20.70V (was on phone earlier - typos)
    RMS = pk/2= 32.52V

    P = I^2 * R = Vrms^2/R

    P = 32.52^2/10 = 105.75W

    Edit: Fixed them numbers up, I hope I didn't confuse you with the original errors.


  • #3
    Copper_pipe
    Registered Users, Registered Users 2 Posts: 11,553 ✭✭✭✭Copper_pipe


    This was my first attempt


  • #4
    BrianDug
    Registered Users, Registered Users 2 Posts: 163 ✭✭BrianDug


    You are on the right track so.

    I didn't subtract the voltage drop on the diode from the answer.


  • #5
    ted1
    Registered Users, Registered Users 2 Posts: 23,586 ✭✭✭✭ted1


    BrianDug wrote: »
    You are on the right track so.

    I didn't subtract the voltage drop on the diode from the answer.

    Is RMS not found using sq root 2?


  • #6
    BrianDug
    Registered Users, Registered Users 2 Posts: 163 ✭✭BrianDug


    ted1 wrote: »
    Is RMS not found using sq root 2?

    Not for this type of circuit. If it was a full sinusoid it would be sqrt(2) alright.

    It can catch you out quiet easily if you are not careful.


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