JC 2014 Maths Paper Two - Mon. June 9th 2014 - all levels

emersyn · 09-06-2014 05:39PM

The paper is up

yaEHya · 09-06-2014 05:47PM

Reckon I got 140 in that paper and 165 in paper one so I got a ****ing d

andyman · 09-06-2014 06:14PM

Higher paper done here. I got 7:8 for Question 10 also.

Liordi · 09-06-2014 06:16PM

andyman wrote: »

Higher paper done here. I got 7:8 for Question 10 also.

How did you find it?

thetalker · 09-06-2014 06:21PM

the hardest question was undoubtedly the one about questioning people at lidl about their favorite place to shop

Liordi · 09-06-2014 06:24PM

thetalker wrote: »

the hardest question was undoubtedly the one about questioning people at lidl about their favorite place to shop

Not a sign of Aldi. :rolleyes:

andyman · 09-06-2014 06:26PM

Liordi wrote: »

How did you find it?

Let r1 = 6cm and r2 = 3cm then apply the formula:

V = π (r1^2 + r1r2 + r2^2) h/3

Answer should leave you with (in terms of pi) 147π

Put that answer over the answer for part (i) and you get a ratio of .875:1 or 7:8

Liordi · 09-06-2014 06:27PM

andyman wrote: »

Let r1 = 6cm and r2 = 3cm then apply the formula:

V = π (r1^2 + r1r2 + r2^2) h/3

Answer should leave you with (in terms of pi) 147π

Put that answer over the answer for part (i) and you get a ratio of .875:1 or 7:8

I meant the paper in general.

Thanks, though

andyman · 09-06-2014 06:31PM

Liordi wrote: »

I meant the paper in general.
Thanks, though

It seemed very fair to me. I know a lot of people were afraid yesterday because of a nice paper 1 but it was nice to see they were just nervous.

Question two was very badly worded, which is an ongoing issue in Project Maths. I think the general idea was clear but a lot of students could easily have had to read it a couple of times.

Liordi · 09-06-2014 06:33PM

andyman wrote: »

It seemed very fair to me. I know a lot of people were afraid yesterday because of a nice paper 1 but it was nice to see they were just nervous.

Question two was very badly worded, which is an ongoing issue in Project Maths. I think the general idea was clear but a lot of students could easily have had to read it a couple of times.

Oh, are you a teacher or something?

andyman · 09-06-2014 06:35PM

Liordi wrote: »

Oh, are you a teacher or something?

Yes, just newly qualified.

Liordi · 09-06-2014 06:35PM

andyman wrote: »

Yes, just newly qualified.

Did you post the solutions online?

MangoMachine · 09-06-2014 06:39PM

andyman wrote: »

Yes, just newly qualified.

Hm if you could post a link with the solutions it would be brilliant!

MangoMachine · 09-06-2014 06:44PM

Answer to 8 (iii) anyone?

Liordi · 09-06-2014 06:46PM

MangoMachine wrote: »

Answer to 8 (iii) anyone?

x - 3y - 7 = 0

Emmie123 · 09-06-2014 06:48PM

So happy with how paper 2 went! Hopefully that's pushed me to a high B

roisiny · 09-06-2014 06:56PM

DanielChester wrote: »

PS. That theorem of the circle was such a surprise, good thing I learned it the day before, I had doubts it would come up after seeing it in a previous exam paper.

Got up at 6:45 and learnt it this morning, even though my body was not impressed with six hours sleep

Kelly090 · 09-06-2014 07:01PM

Can some one tell me how to do question 8? Thanks

andyman · 09-06-2014 07:05PM

Liordi wrote: »

x - 3y - 7 = 0

This.

andyman · 09-06-2014 07:07PM

Kelly090 wrote: »

Can some one tell me how to do question 8? Thanks

Which part in particular? Or all of it?

Liordi · 09-06-2014 07:07PM

Kelly090 wrote: »

Can some one tell me how to do question 8? Thanks

(i)
x - 3y - 6 = 0
Divide the whole line by three.
1/3x - y - 6 = 0.
Slope = 1/3.

OR

Let x = 0 let y = 0
0 - 3y - 6 = 0 x - 3(0) - 6 = 0
-3y = 6 x - 6 = 0
y = -2 x = 6
Point: (0, -2) Point: (6, 0)

y2 - y1

x2 - x1

0 - (-2)

6 - 0

2/6 = 1/3

(ii)
Just sub it in.
1 - 3(-2) - 6 = 0
1 + 6 - 6 = 0
1 =/= 0
=> The point (1, -2) isn't on the line.

(iii)
We know the point (1, -2) is on the line and as the line is parallel to the above line, m = 1/3.

y - y1 = m (x - x1)
y - (-2) = 1/3 (x - 1)
To neutralize the fraction; we multiply by 3.
3y + 6 = x - 1
x - 3y - 7 = 0.

ElmW13 · 09-06-2014 07:13PM

roisiny wrote: »

Got up at 6:45 and learnt it this morning, even though my body was not impressed with six hours sleep

Same!!! For some weird reason I woke exactly an hour before my alarm was meant to go off... weird

Kelly090 · 09-06-2014 07:30PM

Liordi wrote: »

(i)
x - 3y - 6 = 0
Divide the whole line by three.
1/3x - y - 6 = 0.
Slope = 1/3.

OR

Let x = 0 let y = 0
0 - 3y - 6 = 0 x - 3(0) - 6 = 0
-3y = 6 x - 6 = 0
y = -2 x = 6
Point: (0, -2) Point: (6, 0)

y2 - y1
x2 - x1

0 - (-2)
6 - 0

2/6 = 1/3

(ii)
Just sub it in.
1 - 3(-2) - 6 = 0
1 + 6 - 6 = 0
1 =/= 0
=> The point (1, -2) isn't on the line.

(iii)
We know the point (1, -2) is on the line and as the line is parallel to the above line, m = 1/3.

y - y1 = m (x - x1)
y - (-2) = 1/3 (x - 1)
To neutralize the fraction; we multiply by 3.
3y + 6 = x - 1
x - 3y - 7 = 0.

Thanks so much!!!:)

MangoMachine · 09-06-2014 07:35PM

Anyone know the marking scheme? Or at least have an idea?

MangoMachine · 09-06-2014 07:46PM

Can you get junior cert results online?

emersyn · 09-06-2014 09:49PM

MangoMachine wrote: »

Anyone know the marking scheme? Or at least have an idea?

To get a rough estimate multiply the time recommended for each question by 2, e.g. if it says to spend 10 minutes on a question it's generally about 20 marks. We won't know the exact marking scheme until September

Caral · 10-06-2014 08:33AM

I got 5.6m for the new height
I got 1:8 for the ratio
I got my angle to be 59 degrees.. Anyone else get these ... Did we actually have to use the frustrum formula? Its not on our course like...

Caral · 10-06-2014 08:35AM

Liordi wrote: »

Yeah.

No 6.403 was your distance AB

mayway · 10-06-2014 09:59AM

S_Hick12 wrote: »

Is 0.875:1 the same as 7:8?

Yes, it is.

***JC 2014 Maths Paper Two - Mon. June 9th 2014 - all levels***

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JC 2014 Maths Paper Two - Mon. June 9th 2014 - all levels