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Problem solving using algebra

  • 04-03-2014 09:56PM
    #1
    12dlsam
    Registered Users, Registered Users 2 Posts: 5 ✭


    A metal alloy is 30% nickel. Another metal alloy is 70% nickel. The two alloys are mixed to produce 20kg of a metal alloy that is 48% nickel. How much of each metal alloy is used?"

    Can anyone help me in writing out this equation please


Comments

  • #2
    Pherekydes
    Registered Users, Registered Users 2, Paid Member Posts: 16,307 ✭✭✭✭Pherekydes


    Let x equal the mass of 30% nickel alloy and y equal the mass of 70% nickel alloy.

    Then,

    x+y = ?

    0.3x + 0.7y = ?

    Can you fill in and solve?


  • #3
    12dlsam
    Registered Users, Registered Users 2 Posts: 5 ✭12dlsam


    so x + y = 20
    0.3x + 0.7y =0.48
    ??? simultaneous equations from here??


  • #4
    Pherekydes
    Registered Users, Registered Users 2, Paid Member Posts: 16,307 ✭✭✭✭Pherekydes


    12dlsam wrote: »
    so x + y = 20
    0.3x + 0.7y =0.48
    ??? simultaneous equations from here??

    Your second equation should read

    30% of something (x) plus 70% of something (y) equals 48% of ??

    Once you correct the right hand side you can easily solve using simultaneous equations.


  • #5
    12dlsam
    Registered Users, Registered Users 2 Posts: 5 ✭12dlsam


    Got it, thanks a million for all your help.


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