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gambling math problem

  • 23-02-2011 04:35PM
    #1
    crazygeryy
    Closed Accounts Posts: 3,065 ✭✭✭


    there were 92 soccer games on yesterday.29 of them were draws.

    id like to know my odds on picking 4 of them to be draws.in other words picking 4 out of the 92 to be draws.can anyone work that out?just curiousity.
    and im useless at maths.


Comments

  • #2
    UrbanSea
    Closed Accounts Posts: 18,335 ✭✭✭✭UrbanSea


    Could I be right in saying that if you wanted the % you'd put 4 over 92 and multiply it by one hundred. However,that would be assuming that all teams would be of the same quality and odds.
    Maybe I'm way off there,which I probably am.


  • #3
    UrbanSea
    Closed Accounts Posts: 18,335 ✭✭✭✭UrbanSea


    Edit: That would be for four individual draws,not ones in particular.


  • #4
    jprender
    Registered Users, Registered Users 2 Posts: 1,427 ✭✭✭jprender


    118/1


  • #5
    clived2
    Registered Users, Registered Users 2 Posts: 546 ✭✭✭clived2


    119 to 1


  • #6
    clived2
    Registered Users, Registered Users 2 Posts: 546 ✭✭✭clived2


    jprender wrote: »
    118/1
    lols i rounded up


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  • #7
    crazygeryy
    Closed Accounts Posts: 3,065 ✭✭✭crazygeryy


    wow high odds.so its hard to pick 4 draws lol

    thankyou for solving it for me.


  • #8
    Im Only 71Kg
    Closed Accounts Posts: 400 ✭✭Im Only 71Kg


    jprender wrote: »
    118/1

    how did you come up with this number? can you show us the math involved..thanks


  • #9
    clived2
    Registered Users, Registered Users 2 Posts: 546 ✭✭✭clived2


    There are 92 games, 29 draws,

    Imagine a bowl with 92 balls in it, 29 blue and the rest black,

    What are chances of picking a blue ball in your first go

    29 out of 92 29/92

    and the chance of a blue in your second 28/91 and so on


    27/90
    26/89

    So you have

    29/92= .315 = 1 divide by .315= 3.18 odds
    28/91= .308 = 1 divide by .308= 3.25 odds
    27/90= .3 = 1 divide by .3 = 3.33 odds
    26/89= .29 = 1 divide by .29 =3.45 odds


    3.18 x 3.25 x 3.33 x 3.45 = 118.7


  • #10
    crazygeryy
    Closed Accounts Posts: 3,065 ✭✭✭crazygeryy


    clived2 wrote: »
    There are 92 games, 29 draws,

    Imagine a bowl with 92 balls in it, 29 blue and the rest black,

    What are chances of picking a blue ball in your first go

    29 out of 92 29/92

    and the chance of a blue in your second 28/91 and so on


    27/90
    26/89

    So you have

    29/92= .315 = 1 divide by .315= 3.18 odds
    28/91= .308 = 1 divide by .308= 3.25 odds
    27/90= .3 = 1 divide by .3 = 3.33 odds
    26/89= .29 = 1 divide by .29 =3.45 odds


    3.18 x 3.25 x 3.33 x 3.45 = 118.7


    bravo! im impressed and thanks.


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