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integrate x/(2x^2 -3) ??

30-01-2010 03:53PM

#1

Ste234

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integrate x/(2x^2 -3) ??

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#2 30-01-2010 04:15PM

eoins23456

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let u equal the bottom
u=2x^2 +3
du=4x dx
1/4du= x dx
integrating 1/u give ln u and substituting gives 1/4ln2x^2+3

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#3 30-01-2010 04:44PM

Fad

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Wolfram Alpha says

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