Permissions - passing a file as the argument

magnia · 10-09-2007 12:07PM #1

this is the only way i can think of to do this but there must be a better way or else im gonna end up writing 200 lines of copy and pasting code.

echo ' READ WRITE EXECUTE'

own=$(ls -al $1 |cut -c2)

if ($own==r) then
first=yes
else
first=no
endif
echo $first

Im writing a script that takes a file as an argument and it basically checks the permissions the owner and group and everbody has for the file passed in.
I need the output to look something like this

READ WRITE EXECUTE
OWNER LEE.BALLANCORE YES YES NO
GROUP USERS YES NO NO
EVERYBODY NO NO NO

magnia · 10-09-2007 04:24PM

i got this to work but not exactly the way i wanted it to. can anyone think of how to improve it?

#!/bin/bash

echo ' r w x'

own=$(ls -al $1 |cut -c2)
if [ $own = "r" ] ; then first=y; else first=n; fi
# echo $own

own1=$(ls -al $1 |cut -c3)
if [ $own1 = "w" ] ; then second=y ; else second=n; fi
# echo $own1

own2=$(ls -al $1 |cut -c4)
if [ $own2 = "x" ] ; then third=y; else third=n; fi
# echo $own2
echo OWNER $first $second $third

own3=$(ls -al $1 |cut -c5)
if [ $own3 = "r" ] ; then fourth=y; else fourth=n; fi
#echo $own3

own4=$(ls -al $1 |cut -c6)
if [ $own4 = "w" ] ; then fifth=y; else fifth=n; fi
#echo $own4

own5=$(ls -al $1 |cut -c7)
if [ $own5 = "x" ] ; then sixth=y; else sixth=n; fi
# echo $own5
echo GROUP $fourth $fifth $sixth

own6=$(ls -al $1 |cut -c8)
if [ $own6 = "r" ] ; then seventh=y; else seventh=n; fi
#echo $own6

own7=$(ls -al $1 |cut -c9)
if [ $own7 = "w" ] ; then eighth=y; else eighth=n; fi
#echo $own7

own8=$(ls -al $1 |cut -c10)
if [ $own8 = "x" ] ; then ninth=y; else ninth=n; fi
#echo $own8
echo OTHER $seventh $eight $ninth

Steveire · 10-09-2007 06:25PM

Can you use python? The stat module might be useful.

http://www.ibm.com/developerworks/aix/library/au-python/

Permissions - passing a file as the argument

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