This program I have to do

Sandals · 12-02-2006 06:52PM #1

so this is the c++ program I have to make

Sample interaction (but don’t feel totally constrained by this):
Enter a company code, and number of shares held: BOI 100
Enter the day month and year of purchase of these shares: 3 7 2005
100 BOI purchased for £2015.00, today worth £2022.00, gain of 3.47%
Do you have more shares? Y
Enter a company code, and number of shares held: FFA 350
Enter the day month and year of purchase of these shares: 22 11 1999
350 FFA purchased for £7112.00, today worth £7077.00, loss of 0.5%
Do you have more shares? N
Total purchase price was £9127.00.
Current value is £9099.00.
Loss since purchase of £28.00 or 0.3% of £9127.00

And I have until where theyask ou "Do you have more shares" bit,
how do i set it up to recognise the y for yes or n for no if you get me

I need to do a while loop that will keep looping while the value is y(as in yes),
but how do I set that up?
is it some kind of character as in while (x==n),

I'm sure it's easy but I cant figure it out.

Karoma · 12-02-2006 06:54PM

You didn't even specify which language... gah!

Read in a Char from the keyboard...
Look up "loops" do While or if or.. there's a dozen ways to do it

Is it that you don't know how to read input from a keyboard? Or that you don't know about different types? Or that you don't know loops?
What year are you in ?
oO

Sandals · 12-02-2006 06:55PM

sorry that was stupid of me it's c++

Smellyirishman · 12-02-2006 07:35PM

My C++ is none existant so bear with me.

Very simplistically your looking at

char input = 'y'

while( input == 'y' || input == 'Y')
read in shares
std::cout << "Do you have more"
std::cin >> input

finish up

Sandals · 13-02-2006 01:54AM

THESE THREE LINES ARE NOT WORKING;

cout << "Do You have more shares (y/n)?";
cin >> x;
while (x == "y"){

BrokenArrows · 13-02-2006 02:12AM

they should work. Its perfect code. lol

Anyway what do you mean by not working?
Not doing what you want?
Not compiling?

Smellyirishman · 13-02-2006 10:44AM

You cannot test equivilance on Strings using ==, you must use a function.
I think the function in C++ is Compare(String A, String B, bool ignoreCase). This function returns a float depending on whether the string is "lesser" ( returns < 0 I think) or "greater" ( > 0), if they are equal then 0 is returned.

So in order to check if the char entered ( x in your case ) is equal to 'y' then you must use the single character quotes. IE;

while ( x == 'y' )

using a string it would be

while ( Compare(x,"y",true) == 0 )

Did you import the libraries for IO? Try using std::cin and std::cout instead.

Again, take this with a pinch of salt.

Sandals · 13-02-2006 08:04PM

I dont know how to import the libraries for Io,
what should I call x,
is it an int or a char
like
int x;
or char x[2];

? thanks for your help.

Sandals · 13-02-2006 08:17PM

This is what I have, and some where here the problem lies, the rest of program works fine;

char companycode[80],t[80];
int number_shares,day,month,year,pday,pmonth,pyear;
cout << "Do You have more shares (y/n)?";
cin >> t;

while ( t == 'y' ){

Smellyirishman · 13-02-2006 08:45PM

K, well I don't want to give too much away...

Here is the entire, 100% working code to do a while loop reading in "shares" until the user enters something other than y.
It's very basic and straight forward, if your stuck on any of it say so.

#include  <iostream>

using std::cout;
using std::cin;
using std::endl;

int main()
{
    int share = 0;
    char input = 'y';
    
    while( 'y' == input ) 
    { 
           cout << "Please enter new share value  ";
           cin >> share;
           cout << endl;
           cout << "Valude entered was : " << share;
           cout << endl;
           cout << "Do you want to enter more shares?";
           cin >> input;
    }
    
    return 0;
}

This program I have to do

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