anyone know some gd

handandshrimp · 07-12-2004 06:14PM #1

I'm a student trying to do a project
What I crave is to create an online shop for placing images on a t-shirts

My big problem is allowing the user to dynamically resize an image on to a t-shirt, I've started this by setting up a Easyphp server and configuring it with a php extension for php_gd2. This I got working fine. I then got a lovely bit of code from
http://www.phpbuilder.com/snippet/detail.php?type=snippet&id=1211
And this, I think, is what I need to get going. I'm so clueless, hoping that someone can help.

I have this code:

<?php
$imgfile = ($_GET);
$percent = ($_GET);

header('Content-type: image/jpeg');

list($width, $height) = getimagesize($imgfile);
$newwidth = $width * $percent;
$newheight = $height * $percent;

$thumb = ImageCreateTrueColor($newwidth,$newheight);
$source = imagecreatefromjpeg($imgfile);

imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight,
$width, $height);

imagejpeg($thumb);
?>

also I have a script to call it with

why??????????????

Ivan Dunaev · 08-12-2004 08:31AM

why what?

is it misprint - "<img scr=..."? may be "<img src=..." will be better?

ressem · 08-12-2004 02:45PM

The image tag "script", img src, is put at the point in your html at which you want the image to be displayed.

The PHP code is saved as a file, "resizer.php" on your server. The subdirectory in which you place it depends on your server setup.

handandshrimp · 08-12-2004 03:05PM

Thanks guys

stupid spelling! but it didn't work:(. the error's i'm getting are:
if I put php tags in

Parse error: parse error, unexpected '<' in c:\easyphp1-7\www\test3.php on line 11

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>

<?php
<img src="resizer.php?imgfile=image.jpg&percent=0.3" border=0>
?>
</body>
</html>

or if I have not php tages I get a small broken image which if I try and view with firefox I get :

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>

<?php
<img src="resizer.php?imgfile=image.jpg&percent=0.3" border=0>
?>
</body>
</html>

The image “http://localhost/resizer.php?imgfile=image.jpg&percent=0.3” cannot be displayed, because it contains errors.

I did save it as resizer.php in the right folder, although I did call the html document test3.php but I don't think that matters, does it?

I'm pretty sure the mistake is somewhere hear, all though I might be wrong:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>

<img src="resizer.php?imgfile=image.jpg&percent=0.3" border=0>

</body>
</html>

you guys rock and thanks for the help!!!!!!!!!!

ressem · 08-12-2004 04:02PM

The guys that provided the php use it like

<img border='0' src='resizer.php?imgfile=smp.jpg&percent=0.6'>

http://smallcapitalbusiness.com/resizer/sample.php
Choose a new size and view source.

handandshrimp · 08-12-2004 11:24PM

Just wanted to say a big thank you!!!! YOU’RE A GENIUS!!!! Thank you sooo much!!! It’s exactly what I need!!! XXX

anyone know some gd

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