Simple Perl/CGI Question

Renton · 30-07-2001 02:48PM #1

     if($rent_parse2 eq " ")
     {
        $stupid_2=$stupid-10;
        $stupid_2=$stupid_2+$count2;
        $whatout = substr($FORM{'comment'}, $count, $stupid_2);
        $count2=10;
     }

Im only learning perl a bit, and while thats crude enough in its self, Just one thing I need to know is this:

this line
if($rent_parse2 eq " ")

Does not catch it, is there some sort of function or something that I should replace " " with?

Thanks

RentZ

Chubby · 30-07-2001 03:31PM

The code looks correct if you are comparing the string variable $rent_parse2 to a white space.

Try this to confirm the comparison to space works.
$huh = " ";
if($huh eq " "){
print "huh\n"
}

So only conclusion is what $rent_parse2 doesn't have the value " " (a space) when the code reaches the if statement. Put the following line before it reaches the if statement to see what value it has.

print $rent_parse2

[This message has been edited by Chubby (edited 30-07-2001).]

Baz_ · 30-07-2001 05:01PM

What are you trying to do witht that code mate???

Gavin · 31-07-2001 09:08AM

Perchance try

if("$rent_parse2" eq " ")

Include the quotes around the variable. If it's just a blank variable you are looking for, then perl will default that to a boolean false .. i think.

ie,

if($rent_parse)
{
print "true, text in the variable" ;
}

Gav

Gav

-gAuD- · 07-09-2001 01:04PM

what are you trying to do ??

what are you testing for ?? whitespace ?? empty string ?? undef ??

Are you sure the value of the string $rent_parse2 is what you think it is ??

Simple Perl/CGI Question

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