Java - Printing arguments in reverse order

empirix · 16-01-2004 02:11PM #1

Lads/Lassies,

I'm sure this will be trivial, so i'd appreciate the help, i'm trying to learn a bit of java on my own

What code do i need to print out command line arguments in reverse order.

public class MyCode {
public static void main (String [] args) {
for (int i=0; i < args.length; i = i + 1)

System.out.println ( args );
}
}

Any help appreciated

If anybody knows any handy sites for java let me know
thanx

seamus · 16-01-2004 02:17PM

Ah, you're almost there.

The only thing you need to think of is that for each value of i from 0 to args.length, you're printing out the value in args.
To print them out backwards all you need to do is alter the for() loop, so that i goes from args.length -1 down to 0.

I'm intentionally not giving you the code btw

empirix · 16-01-2004 02:48PM

Doh---I can't get this , I can't get this, I think I have done everything bar reverse them:mad:

The memories are coming back to why i packed in programming after my diploma

seamus · 16-01-2004 03:29PM

Just change your for loop to read

for(int i = (args.length - 1); i >= 0; i--)

empirix · 16-01-2004 03:40PM

Thanx for that Seamus, I wouldn't of cracked that.
I think I will have to hit the books or get a few grinds

Java - Printing arguments in reverse order

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