Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Listview problem

  • 29-01-2003 1:45pm
    #1
    jessy
    Registered Users, Registered Users 2 Posts: 950 ✭✭✭


    Hello All

    I have a small problem where I am trying to read data from a 4 column listview set to report style if someone could give me a code example on how to read more than the first column (preferably all columns) I would be grateful.
    the programming language is borland c++ builder 4:cool:


Comments

  • #2
    Talliesin
    Closed Accounts Posts: 9,314 ✭✭✭Talliesin


    How is the listview created? "Raw" Windows listview, "Raw" listview from some other OS, or a framework class?


  • #3
    dazberry
    Registered Users, Registered Users 2 Posts: 2,152 ✭✭✭dazberry


    Jessy

    Since you're using C++ Builder 4 I'm guessing you're using the VCL. Its about 6 yrs (!!! - I didn't realise it was so long until now - f) since I've done any C++, but from the VCL point of view, the following will get you on the right track (in Delphi). I guess, replace := with = and . with -> (don't quote me on it) and all the other bits ;)

    var
    LI : TListItem;
    begin
    LI:=ListView1.Items[0];

    Label1.Caption:=LI.Caption;
    Label2.Caption:=LI.SubItems.Strings[0];
    Label3.Caption:=LI.SubItems.Strings[1];
    Label4.Caption:=LI.SubItems.Strings[2];
    end;

    Things to note.

    Subitems is of type tStrings, so Subitems.count, Subitems[index] / Subitems.strings[index], Subitems.objects[index] etc. are all valid. So all those "rules" (ignored above) apply.

    HTH

    D.


Advertisement