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Puzzle

  • 14-12-2002 11:26pm
    #1
    Closed Accounts Posts: 1,114 ✭✭✭


    A friend of mine gave me this particular puzzle I'm trying to solve it and I can't. It's a rectangle and inside the rectangle is divided into five boxes, two one top and three on the bottom. They're staggered like brickwork. The object of the puzzle is to draw a continuous line that crosses each line in this box once but no more than once, and there's a total of 16 lines.

    I think that it can't be done but if you can do it please post it up here but be careful you'll think you have it then you cop on that you don't!:D


Comments

  • Closed Accounts Posts: 3,299 ✭✭✭oeNeo


    guh no idea


  • Closed Accounts Posts: 1,975 ✭✭✭Oeneus


    Are you only allowed to draw on line?
    and Does this include the outside/wall lines of the box?


  • Closed Accounts Posts: 272 ✭✭wiensta


    doubt it can be done by a continuous line!


  • Registered Users, Registered Users 2 Posts: 2,621 ✭✭✭Panda


    the closest you can get to completing the puzzle is this


  • Registered Users, Registered Users 2 Posts: 2,621 ✭✭✭Panda


    try drawing this image in one continous line.


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  • Closed Accounts Posts: 1,975 ✭✭✭Oeneus


    Originally posted by Panda
    try drawing this image in one continous line.

    Too easy...too old! My Grandfather taught me that when I was six.


  • Closed Accounts Posts: 2,590 ✭✭✭lordsippa


    Start at the bottom right corner, following the lines of the puzzle go up and then follow down the middle line and then go up to the top left corner. Duh.


  • Registered Users, Registered Users 2 Posts: 5,356 ✭✭✭NeVeR


    Originally posted by Kappar
    A friend of mine gave me this particular puzzle I'm trying to solve it and I can't. It's a rectangle and inside the rectangle is divided into five boxes, two one top and three on the bottom. They're staggered like brickwork. The object of the puzzle is to draw a continuous line that crosses each line in this box once but no more than once, and there's a total of 16 lines.

    I think that it can't be done but if you can do it please post it up here but be careful you'll think you have it then you cop on that you don't!:D


    I tried it for ages. couldnt get it , anyone get it ?


  • Registered Users, Registered Users 2 Posts: 5,356 ✭✭✭NeVeR


    Is this liek the old dot and circle one? (attached)

    where u have to draw the dot and full circle with out taken the pen from the page?

    if it is then all you do is use a different page and when you draw the dot move your pen on to the other page so there is no line from the dot to the circle and then once you are away from the dot put the pen back on the same page as the dot and draw the circle.

    if it is i'd say you can draw a line through all the lines.


  • Registered Users, Registered Users 2 Posts: 3,172 ✭✭✭Don1


    I can cross fifteen out of the sixteen without crossin the same one twice. I'm goin mad here doin it. :mad: I'll give up eventually, but as long as I have sight in at least one eye and partial sanity I'll keep goin!:D


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  • Closed Accounts Posts: 286 ✭✭Kev


    It's impossible, and can be proved.


  • Registered Users, Registered Users 2 Posts: 3,172 ✭✭✭Don1


    Go ahead then before i go totally cuckoo!!!!!!!!:eek:


  • Closed Accounts Posts: 286 ✭✭Kev


    there are 3 boxes with 5 sides and 2 with 4 sides, for the boxes with 5 sides the line must begin or end inside it, which would be fine if there were only 2 such boxes as a line has only 2 ends.


  • Closed Accounts Posts: 8,478 ✭✭✭GoneShootin


    should be able to be done using Graph Theory, but im far too lazy :D


  • Closed Accounts Posts: 286 ✭✭Kev


    You could show its impossibility using graph theory.


  • Closed Accounts Posts: 1,114 ✭✭✭Kappar


    If anyone would like to post the proof of how this can't be done using the Graph Theory :confused: I would love to stick it in someone's face ;)


  • Closed Accounts Posts: 1,114 ✭✭✭Kappar


    I found this tool to do Graph theory but as you would expect i don't understand it but if anyone wants to get it you can at http://www.geocities.com/pechv_ru/load.html


  • Registered Users, Registered Users 2 Posts: 9,046 ✭✭✭Dustaz


    May i introduce you to our good friend mr Img Tag


  • Registered Users, Registered Users 2 Posts: 19,608 ✭✭✭✭sceptre


    12 nodes, 16 arcs, therefore Euler's Theorem says you can't

    (look up "Euler" and "Konigsberg" on google for a nice simple explanation)


  • Closed Accounts Posts: 1,651 ✭✭✭Enygma


    Pfff! Easy!


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  • Registered Users, Registered Users 2 Posts: 3,172 ✭✭✭Don1


    Ya fecker. If I'd known it was that simple I'd have more hair left!


  • Closed Accounts Posts: 286 ✭✭Kev


    Originally posted by sceptre
    12 nodes, 16 arcs, therefore Euler's Theorem says you can't

    (look up "Euler" and "Konigsberg" on google for a nice simple explanation)

    What do you mean ?

    Of what relevance are the number of nodes and arcs ?

    as far as i can see there are 6 nodes and 16 arcs, and it is not possible because more than two of the nodes have an odd number of arcs.


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