Paladins Puzzles No.4

Paladin

Alf, Bert and Jak play a card game using the ace of spades up to the 10 of spades (ace being a one) which are shuffled and placed face down on the table.
The players draw a card in turn and must state whether it is odd or even. Playing in turn, on drawing a second card they must declare a number, being either the sum or the product of the cards held- provided they cannot win the game.
To win the game a player must correctly state what cards are remaining on the table.
The players are perfect logicians and us all the data available.
In the first round each pplayer declared "even" (thay all had even numbered cards).
In they socond round alf declared "12" and bill "10".
As Jak reached for his second card a player won the game.
Who had won? What cards did he hold? What cards were remaining?

[This message has been edited by Paladin (edited 23-02-2000).]

WhiteWashMan

not enough info
there are too many variations on product and sums to figure out....
as for who called out..it could have been either alf or bert. it wasnt jak as he was obviously going for his 2nd card
alf could have had either the 10+2, 8+8, 6*2 or 4*3
bert could have had either the 6+4, 8+2, or 2*5
if jak also picked up an even card then it was any of the ones left out (depending on whether a product or addition was used)

or else i just cant figure it out

Paladin

There IS a definate answer to all 3 questions u have wwman.
It is possible and is quite logical.
The answer of course cant be heresay and possibilities. It has to be definate with reasons for the answer.
Good luck

Asuka

Hmmm... cant figure this one out immediately
Ill try again l8r

Swinga

well...first off, WWman, your math isn't exactly spotless.....8+8 is 16, not 12.

second, since you said they cannot win if you declare a number, (and i probably misunderstood it), then jak won.....still working on what cards he was holding/were left

[This message has been edited by Swinga (edited 24-02-2000).]

Ashen

Thats easy........
Alf won obvoiusly
cos while Bert and Jak were off having a toss (in seperate rooms) due to the pornographic nature of the cards,
Alf, him bein a scobe from the mun, ran off with all the cash and beers.
The cards in his hand were the ones where the naked ladies still have a bit of cloth covering their bits or else he would have been off with the other two......
The cards still on the table........well who cares, they were probably too sticky for anyone to find out anyway...
Good one

Paladin

Cmon, surely someone can get it?

the celtic tiger

Well....personally I think that Bert lost for sure cause some guy called Bill came in and took his place. This leaves only Jak and that alien guy. I know for a fact that the Alf character is no spring chicken....but on the other hand ....Jak came out a few months back and since then has undergone some seriouus psychological changes. I think he's more emotionally stable and for that reason only....I'm going to go with Jak.
tct

WhiteWashMan

sorry, that should have been 8+4 =12

the celtic tiger

So....what do you think of my reasoning....good...no?
tct

Guinnessman

a friend figured it out beside me but i dont understand him

Jak

I won.

Paladin

Wahoo. My first post on the new boards and its a "hup"
Basically I want ppl to try their hand at this one. Cmon ppl. Excercise the mind?

---

One ring to rule them all, One ring to to find them,
One ring to bring them all and in the darkness bind them




[This message has been edited by Paladin (edited 25-02-2000).]

WhiteWashMan

THE WINNER WAS ALF BY THE WAY.
woops
winner was alf as he needed to know if bert had got an even or odd card.
which means that alf had two even cards..bear with me..im figuring ut here!
so bert got 10 and must have used a sum of 6 ans 4
which means that the only other way that alf could have got 12 was by 10 plaus 2 (coz he had the other 2 even cards.
which means jak had the 8 of spades
which means the cards left were
ace, three, five seven and nine

now thats not the only answer, but anything else would invole no logic and a lot of guesswork..which is not allowed

do i win a prize?

---

Your Dungeon Is On An Incline.
Irate Creatures Cannot Play Marbles.....

Paladin

Hehe
Despite ure slightly flawed logic you got it right wwman
Ans:
Winner=Alf
Cards held by players:
Alf=2+10
Bert=6+4
Jak=8
Remaining=1,3,5,7,9
Reasoning:
Alf knew after the first round that 3 even cards were gone.
His 12 meant that he must have had another even card since 2 evens added OR multiplied must make another even number.
Then Bert called out 10. This is where the logic comes in. For Bert to get 10 he must have 2 even cards to add (6+4) (8+2) OR if multiplied (10x1) (2x5).
The only way Alf could be certain it was 2 even cards Bert had, was if he had the cards needed by Bert to multiply to get 10 which add to make 12 AND foil one of the combinations of adding to get 10.
They must also be even cards therefore (10+2=12)
Tough eh? Just a little time needed as WWman showed
Next one will b easier

---

One ring to rule them all, One ring to to find them,
One ring to bring them all and in the darkness bind them