PHP: int - char/string conversion and vice versa

Lemming

Hey guys,

just wondering if anyone knows how to convert a string to int (or vice versa) in PHP. I can't seem to find anything in the manual (before someone utters the immortal acrynom )

What I have is this:

$today = getdate() ;
$var1 = 2000 ; // start year
$var2 = $var1++ ;
$var3 = $today ; // current year (taken from system clock)

...
...
...

echo $var1 ;
while($var2 < $var3)
{
echo $var2
$var2++ ;
}
echo $var3 ;

basically what I'm trying to do is create an input field (<select>) which is self-updating as the years roll on so to speak.

The problem is (best as I can make it) that $var3 isn't an integer and that's the stumbling block. So any suggestions would be greatly appreciated

[edit]
Where's C/C++'s itoa or atoi functions when you need them?!!! :ermm:
[/edit]

nahdoic

[PHP]<?php
$today = getdate();
$var1 = 2000 ; // start year
$var2 = $var1++ ;
$var3 = $today ; // current year (taken from system clock)


echo $var1 ;
while($var2 < $var3)
{
echo $var2 ;
$var2++ ;
}
echo $var3 ;

?> [/PHP]

dahamsta

See the section on Type Casting on the Type Juggling page. Also see the intval() and related functions. In the manual.

adam

Lemming

Originally posted by dahamsta
See the section on Type Casting on the Type Juggling page. Also see the intval() and related functions. In the manual.

adam

You, sir, are a legend!!!
I'll even forgive your manual reference (I kinda suspected I was lookin in the wrong places mind you! :rolleyes: )

nahdoic

Gonna stop trying to answer these programming questions. Never seem to understand what people want. Anyway here is another solution too.

[php]<?php
$today = getdate() ;
$var1 = 2000 ; // start year
$var2 = $today ; // current year (taken from system clock)
for($i=$var1;$i<=$var2;$i++)
echo $i;
?>
[/php]