C string manpulation question

Scruff

After years away from it i find myself back doing some C programming

Anywho, heres my problem

I'm passing in a char * into a function that has a carrige return at the end of it. I need it without it for transmission as part of another string to a socket.

I've tried the following:

char text_out[1024];
int str_length = -1;

str_length = (strlen(text_in) -1);
strncpy(text_out, text_in, str_length);
it looks fine but when i receive it at the socket there is "\CC\CC\CC\CC\CC\" until the end of the text until the end of the char array.

satchmo

C Strings are NULL-terminated, in other words the last byte of every string is a 0 to show that that's where the string ends. You're removing the last byte of the string, and so removing the terminator - the program won't know where the string ends.

To remove the carriage return you'll want to remove the last byte and change the second last byte (the return) to 0.

Beano

You dont even need to remove the last byte, just do

text_in[strlen(text_in) -1]=0

satchmo

True - removing the last byte too is just me being anal.

Scruff

Cheers lads and\or lassies!
That did the trick. Had overlooked that that text_in was an array of chars as well. Ah C strings, they're marvelous :rolleyes:
Thanks again.