Maths Paper 2 answers

*marie*

Does anyone know if the answers to paper two will be available anywhere?Just to put my mind at rest...

mrs. hamlet

They will prob b puttin them up on the 806 website 2nite! Well they did the nite of paper 1 anywho!

*marie*

OK thanks!

Fortinbras'

mrs. hamlet wrote:

They will prob b puttin them up on the 806 website 2nite! Well they did the nite of paper 1 anywho!

whats the 806 website?

OTliddy

whats the 806 website?

mrs. hamlet

Countdown to 8 06 on 2FM with the reeeealllly annoying presenter! Just go to the 2FM website then 806 and there should be a link!
if they hav put the answers up... o never mind! :rolleyes:

Cutie18Ireland

www.leavingcertsolutions.com

Sully

Cutie18Ireland wrote:

www.leavingcertsolutions.com

Nope.

I can get them done for you, my girlfriends father writes maths book and has offered. Dunno how long it will take tho.

pingu_girl

anybody get the soloutions yet?

rose**

havent come across any answers yet...anyone else know where i could get them?

Sully

Ill see if I can get them done

TaraC

the answers are up on 2fm now

sixdraw

sorry for bringing up maths again but can anyone tell me how john brennan gets 3/(root 26) on ques. 3(c)(i). i keep gettin 24 / (root26 * root 32).
dot product over the two modulus' right yeah?

Breezer

sixdraw wrote:

sorry for bringing up maths again but can anyone tell me how john brennan gets 3/(root 26) on ques. 3(c)(i). i keep gettin 24 / (root26 * root 32).
dot product over the two modulus' right yeah?

Are you sure it's not -24/(root 26 * root 32)? That's what I got and part (ii) worked out as 3 then

sixdraw

how could there be a negative on top if all the coefficents of the i's and j's are positive. you multiply the i's by the i's and the j's by the j's for the dot product, no? so positive by positive gives positive.

Study???

Ya i got that positive answer two. Phew I thought i was the only 1.....

sixdraw

there's an example in that less stress more sucess.its the same thing as that question and the method is the same as mine so how is john brennan gettin a different answer

Crumbs

sixdraw wrote:

sorry for bringing up maths again but can anyone tell me how john brennan gets 3/(root 26) on ques. 3(c)(i). i keep gettin 24 / (root26 * root 32).
dot product over the two modulus' right yeah?

24/(sqrt(26).sqrt(32)) can be further reduced down to 3/sqrt(13). I suppose that's what John Brennan was trying to do, but made some mistake (or typo) to get 3/sqrt(26).

Breezer

sixdraw wrote:

how could there be a negative on top if all the coefficents of the i's and j's are positive. you multiply the i's by the i's and the j's by the j's for the dot product, no? so positive by positive gives positive.

Yeah but did you not have to reverse the direction on one of the vectors so you could keep going in the one direction round the angle? Oh well, don't care, done nearly a week at this stage and it's not gonna be a lot of marks anyway