Java Programming Issue

roar_ie

I have a string of hex values, e.g. "6A 13 20 CB 20 31"

I parse the string using a StringTokenizer to get the individual hex values:
6A
13
20
CB
etc.

I then iterate over the hex values converting each one to a byte and adding it to a byte array. I use Byte.parseByte method to convert the string hex value to the byte value. However every time I get to the CB value an exception is thrown as follows:
java.lang.NumberFormatException: Value out of range. Value:"CB" Radix:16
at java.lang.Byte.parseByte(Byte.java:124)
at com.openjawx.opodo.utils.DecodeProcess.loadFromRuleStr(DecodeProcess.java:306)
at com.openjawx.opodo.utils.DecodeProcess.getKEK(DecodeProcess.java:94)
at com.openjawx.opodo.utils.DecodeProcess.doDecode(DecodeProcess.java:108)
at com.openjawx.opodo.utils.DecodeProcess.main(DecodeProcess.java:60)

Any ideas as to how I can get around this issue?

Thanks
roar_ie

daymobrew

The problem is that the range of Byte is -80 to 7F.
See a thread about it on Google Groups.

ressem

You are using
Byte.ParseByte(x,16)?

You can't just use an array of ints/shorts to store results?

ParseByte is a wrapper around ParseInt with a built in boundary check, that means you can't use it unless you are sure that no bytes are above 7F.

There's a check in the Java code that throws this exception if
i=Integer.ParseInt(x,16) returns a result < -128 or > 127.

roar_ie

Cheers, that was spot on.

roar_ie