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Delta T on radiator spec sheet

  • 27-07-2022 10:12AM
    #1
    Registered Users, Registered Users 2 Posts: 7,786 ✭✭✭


    Hi all,

    Just a quick one. I'm looking for new rads and the majority of spec sheets show the Delta T with degrees C, but I've found a minority with K in place of C (I'm assuming this might be Kelvins?) For example ∆t=50K, is this something I need to factor in or is it just a quirk between manufacturers?


    Cheers,


    C



Comments

  • Registered Users, Registered Users 2, Paid Member Posts: 8,245 ✭✭✭MrMusician18


    Just a quirk. Kelvin's and Celsius are the same size unit but have a different starting point



  • Registered Users, Registered Users 2 Posts: 7,786 ✭✭✭circadian


    Thanks. I understand that Kelvins start from absolute zero, which means ∆t=50K means the radiator runs at -223.15 Celsius? That doesn't add up.



  • Registered Users, Registered Users 2, Paid Member Posts: 8,245 ✭✭✭MrMusician18


    A delta T is the difference between two temperatures. So the difference between the temp of the radiator and the ambient air is a delta T, or the difference between the radiator inlet and outlet temperature is also a delta t.



  • Registered Users, Registered Users 2 Posts: 3,175 ✭✭✭cruizer101


    Delta T just refers to the temperature difference, so it doesn't matter if it is K or C its just the difference between two temperatures.

    20C = 293K

    100C = 373K

    373-293 = 80 = 100 - 20



  • Registered Users, Registered Users 2, Paid Member Posts: 8,245 ✭✭✭MrMusician18


    In terms of radiators delta T is used to differentiate between high temperature systems and low temperature ones, delta t = 50 is standard system, like a gas boiler. Radiators have a rated output for a given delta T.

    If you had a low temperature system you might use a delta 30, say for example a heat pump.



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  • Registered Users, Registered Users 2 Posts: 7,786 ✭✭✭circadian




  • Registered Users, Registered Users 2 Posts: 3,772 ✭✭✭John.G


    A 50C Rad (European standard) is the mean (flow+return temps)/2 minus the required room temperature, the calculation for any other deg rad is the (degrad/50)^1.3. Ie a 25deg rad does NOT output 50% of a 50deg rad but a lot less, havnt got my laptop to do the power to calculation.

    It's 40.6% output of its 50deg rating.

    Post edited by John.G on


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