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Sum of two Primes, one of which is 2.

  • 31-01-2018 09:59AM
    #1
    Registered Users, Registered Users 2 Posts: 3,440 ✭✭✭


    1. Am I right in thinking that, if you add any two primes excluding 2 (e.g. 7+11, 23+31, 1+47) you get an even number? i.e. a number divisible by two.

    2. But, if you add any two primes, one of which is 2, (e.g. 2+11, 2+23, 2+31, 2+1, 2+47), you always get an uneven number?

    If I’m correct, has the curious quirk been written about (I’m sure it has) and is there a name for this observation?

    Thanks.

    D.


Comments

  • Registered Users, Registered Users 2 Posts: 170 ✭✭Halfbaker


    I wouldn't call it a quirk. Every prime number larger than 2 is uneven.


  • Registered Users, Registered Users 2 Posts: 68,173 ✭✭✭✭seamus


    Well, it's one of the fundamental rules of maths.

    If you think about it logically, the modulus/remainder of any odd number divided by 2, is 1

    Therefore, every single odd number can be expressed in the form

    (x * 2) + 1

    Thus, adding two odd numbers gives you (x * 2) + 1 + (y * 2) +1 = 2 * (x + y + 1)

    And since any number multiplied by two must be even, the sum of two odd numbers is always even.

    The same rule holds true for 2 + (any odd number).

    Adding them you get 2 + (x * 2) + 1. Since any attempt to divide this equation by 2 will give a non-integer result, it is not an even number.


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