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maths problem

  • 17-05-2017 5:30pm
    #1
    Registered Users, Registered Users 2 Posts: 2


    can someone please tell me how to do 2016 ordinary level maths paper one question 7 I haven't a clue!!


Comments

  • Registered Users, Registered Users 2 Posts: 1,367 ✭✭✭X6.430macman


    8000 divife by100 multiply by 2=160
    8160=244.8. (Divide by 100multiply by 3 this time)

    8160+244.8=8404.8
    8404.8+420.24=8825.04. Divide by 100multiply by 5 this time.

    That's just for option one..hope this helps, come back If you want more guidance


  • Registered Users, Registered Users 2 Posts: 15,397 ✭✭✭✭rainbowtrout


    The question about Paul putting money in the bank?

    Part (a) with the three different interest rates is just:

    8000 x 1.02 = 8160 ( end of year 1)
    8160 x 1.03 = 8404.80 (end of year 2)
    8404.80 x1.05 = 8825.04 (end of year 3)


    Part (b) is compound interest

    The formula is

    Principal x (compound interest)^no of years

    So 8000 x 1.037^3 = 8921.26 after 3 years



    Part (c) give a reason for picking option 1 or 2

    Opt 1: might want to take the money out after a year or two.
    Opt 2: Provides the most interest so he will have more money


    part (d) What rate of compound interest would give 9000 from his 8000 after 3 years.

    You have to use the compound interest formula here and work backwards.

    8000(comp. int)^3 = 9000


    Divide across by 8000:

    (Compound inter)^3 = 9000/8000 = 9/8

    Get the cube root of both sides:
    (Compound interest) = Cube root of (9/8) = 1.04


    1 represents the full amount of money and the .04 the interest

    Compound interest rate = 4%


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