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Hard physics question!!!

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  • 17-09-2016 5:23pm
    #1
    chris241111
    Registered Users Posts: 47 ✭


    HEAT AND HEAT TRANSFER

    120g of copper at 100 degrees celsius is added to 80g of water in a 60g copper calorimeter at 20 degrees. If there is no heat loss to the surroundings, find the final temperature of the system.


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    #2
    rainbowtrout
    Registered Users Posts: 15,381 ✭✭✭✭rainbowtrout


    Is this your homework?

    What are you finding difficult about it?


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    #3
    chris241111
    Registered Users Posts: 47 ✭chris241111


    adding copper to the copper calorimeter I don't know how to do it :( , which one changes temperature the copper, the copper calorimeter or the water?.


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    #4
    chris241111
    Registered Users Posts: 47 ✭chris241111


    I want, just the steps involved in the question,thanks


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    #5
    rainbowtrout
    Registered Users Posts: 15,381 ✭✭✭✭rainbowtrout


    chris241111 wrote: »
    adding copper to the copper calorimeter I don't know how to do it :( , which one changes temperature the copper, the copper calorimeter or the water?.

    All of them change temperature. The copper loses heat and the water and the calorimeter gain heat.

    Heat lost = heat gained

    heat energy lost by copper = heat energy gained by water + heat energy gained by calorimeter


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    #6
    chris241111
    Registered Users Posts: 47 ✭chris241111


    Thanks, I was doing that but tried it again, turns out I was doing 20 minus thetha instead of the otherway around.


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