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Stuck on Integration

  • 23-02-2016 11:09pm
    #1
    Closed Accounts Posts: 11,812 ✭✭✭✭


    I've been working through triple integral for a sphere ( by cartesian) and I've gotten past the 1st stage. Now I'm trying to integrate sqrt(9 -y^2 -z^2 ) dy but getting nowhere fast... any hints?

    I've seen one solution as (ysqrt(9 - y^2 - z^2) + (9 - z^2) arcsin(y/sqrt(9 - z^2) but havn't a clue how he made that leap!:(

    Thanks


Comments

  • Registered Users, Registered Users 2 Posts: 2,149 ✭✭✭ZorbaTehZ


    Your question is too vague, what exactly do you want to integrate. And if it involves a sphere then there is no reason not to make a change to polar coordinates before integrating you only make your life more difficult not doing that.


  • Closed Accounts Posts: 11,812 ✭✭✭✭evolving_doors


    Yes polar would be a lot easier, however the evaluation path I'm on is by using cartesian coordinates only.

    If it makes any difference the y limits are -(sqrt9 -z^2) to +(sqrt9 -z^2) and after that I'll be looking for dz with z limits from -3 to 3


  • Closed Accounts Posts: 11,812 ✭✭✭✭evolving_doors


    or maybe to put it another way... how is this step made?
    378567.jpg
    Integration.jpg


  • Registered Users, Registered Users 2 Posts: 2,149 ✭✭✭ZorbaTehZ


    That step is not trivial and I suspect he/she already explained it in a previous example (based on the 'note').

    It amounts to how might one integrate [latex]\sqrt{c-y^2}[/latex] which is usually carried out by a trigonometric substitution see here


  • Closed Accounts Posts: 11,812 ✭✭✭✭evolving_doors


    Ok thanks, I subbed in (sqrt(9-z^2))sin(theta) instead of y and changed the limits etc. All worked out then:pac:


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