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1Kw PV Panel Array in KWh/m2/year - Any HELP

  • 28-10-2015 11:56PM
    #1
    Registered Users, Registered Users 2 Posts: 376 ✭✭


    Hi all,

    Finding this a bit confusing regarding the PV panels and how much in KWh/m2/year they produce. Could anyone just help me with how it's worked out.

    Say I had a 1Kw PV Panel Array on a roof. What does this produce in typical KWh/year for any given house in Ireland? I know you would divide the total KWh/year by the square area of the house in m2 to get the KWh/m2/year figure.

    Many thanks all


Comments

  • Subscribers, Paid Member Posts: 43,799 ✭✭✭✭sydthebeat


    System Design Part L

    • Apendix M of DEAP Manual;

    The electricity produced by the PV module in kWh/year is

    0.80 x kWp x S x ZPV where S is the annual solar radiation from Table H2 (depending
    on orientation and pitch), and ZPV is the overshading factor from Table H3.

    • Take a system with three off 250W panels. Total panels = 750W or 0.75Kwp
    • Lets assume house has pitch 30 degrees and roof facing SE.
    • Assume shading from Table H3 is “none or very little”. Zpv = 1
    • Output is
    • 0.8 x 0.75Kwp X 1021 X 1 = 612.6KwHrs/Yr.

    http://static.constructionpv.ie/wp-content/uploads/2014/09/ConstructionPV-solar-CPD-presentation.pdf


  • Registered Users, Registered Users 2 Posts: 376 ✭✭delfagio


    Thanks for that Sydthebeat,

    Appreciate the reply. That document helped out quite a lot with understanding it a bit better.

    So from looking at that, would I be right in saying the following:

    Say a house is 200m2 area.

    Thermal renewable energy would need 2000kwh/year.

    Say Thermal Solar Panel achieved 500kwh then this would be 25% of the required renewable energy required. So if adding PV Panel's to be combined, the PV would need to make up the remaining 75% of renewable energy. This would mean, 200m2 x 4kwh/m2/year x 75% = 600kwh required to make up in PV Panels.

    So approximately 3 PV panels with max 250W power output would cover the difference.

    Is this correct??

    So am I right in saying if Thermal Renewable energy requires 10kwh/m2/year and Electric Renewable energy requires 4kwh/m2/year, that basically PV Electric Renewable Energy is 2.5 Times better than Thermal Solar such as tubes or flat plates for hot water etc.

    Many thanks


  • Subscribers, Paid Member Posts: 43,799 ✭✭✭✭sydthebeat


    delfagio wrote: »
    Thanks for that Sydthebeat,

    Appreciate the reply. That document helped out quite a lot with understanding it a bit better.

    So from looking at that, would I be right in saying the following:

    Say a house is 200m2 area.

    Thermal renewable energy would need 2000kwh/year.

    1. Say Thermal Solar Panel achieved 500kwh then this would be 25% of the required renewable energy required. So if adding PV Panel's to be combined, the PV would need to make up the remaining 75% of renewable energy. This would mean, 200m2 x 4kwh/m2/year x 75% = 600kwh required to make up in PV Panels.

    So approximately 3 PV panels with max 250W power output would cover the difference.

    Is this correct??

    So am I right in saying if Thermal Renewable energy requires 10kwh/m2/year and Electric Renewable energy requires 4kwh/m2/year, that basically PV Electric Renewable Energy is 2.5 Times better than Thermal Solar such as tubes or flat plates for hot water etc.

    Many thanks

    yeah its a weird one...

    if your using a mixture of thermal and pv to meet the renewable requirement then the 'electric' renewables counts for 2.5 times what the thermal does.

    for example i did an assessment a while back that had a heat pump, wood stove and pv cells (as the HP and stove didnt get it 'over the line')

    the heap pump offered 6.77 kwh/m2yr
    the wood stove offered 1.91 kwh/m2yr

    that totals out at 8.68 kwh/m2yr

    a 250 w PV cell offered 0.63 kwh/m2yr

    now if you add them all up it only comes to 9.31 kwh/m2yr
    but because the electric is counted as 2.5 the thermal it actually totals out at 10.26 kwh/m2yr

    8.68 + (0.63 x 2.5) = 10.26


    you use the formula i gave a to determine the electric pv input.


  • Registered Users, Registered Users 2 Posts: 376 ✭✭delfagio


    Brilliant Sydthebeat, as always 100% informative response.

    Thanks very much for all your help with my query, you have cleared it all up for me now.

    Thanks again


  • Registered Users, Registered Users 2 Posts: 1,627 ✭✭✭quentingargan


    The only footnote I would put to this is that increasingly I see Deap assessments where EPC or CPC determine the size of solar array - especially if there is a combination of a stove and gas/oil.

    Also, I assume that 2.5 multiplier dates back to a time when the grid took 2.5kwhr of fossil fuel to produce 1kwhr of electricity. With increasing renewables input, that has fallen to 2.37, so I wonder if this ratio will change?


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  • Subscribers, Paid Member Posts: 43,799 ✭✭✭✭sydthebeat


    No Quentin, the 2.5 ratio is the ratio between requiring 4kWh electric versus 10 kWh thermal.


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