Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Complex Fourier Coefficients

  • 24-08-2015 12:43pm
    #1
    Registered Users, Registered Users 2 Posts: 3


    Can anyone help me with this exam question?


    Calculate the complex Fourier coefficients[latex] $C_n$ [/latex] for

    [latex]$$f(x)= |x|- \frac{\pi}{2} , |x|\leq \pi $$[/latex], and [latex]$2\pi$[/latex] periodically continued to all [latex]$x$[/latex].

    I have tried the following;

    [latex]$C_n = \frac{1}{2\pi} {\displaystyle \int_{-\pi}^{\pi} f(x)e^{-inx}dx}$

    $ = \frac{1}{2\pi} \Bigg( {\displaystyle \int_{-\pi}^{0} (-x-\frac{\pi}{2})e^{-inx}dx} + {\displaystyle \int_{0}^{\pi} (x-\frac{\pi}{2})e^{-inx}dx} \Bigg)$ [/latex]

    When I work down through these integrals, I get [latex] $ \displaystyle\frac{(-1)^n}{n^2\pi}$[/latex], whereas I think the answer should be [latex]$\displaystyle \frac{(-1)^n-1}{ n^2\pi}$[/latex]

    Is there something wrong with my approach or is it right and my computation is wrong?

    Thanks


Advertisement