Could somebody work this out for me?

tessat

I'd consider myself good at maths but my head isn't able to work this out today.

Can somebody work out how many unique 6 figure combinations can be made first 26 letter and 0-9 and then 18 letters and 0-9

Many thanks

TheChizler

tessat wrote: »

I'd consider myself good at maths but my head isn't able to work this out today.

Can somebody work out how many unique 6 figure combinations can be made first 26 letter and 0-9 and then 18 letters and 0-9

Many thanks

36×28^5? Just under 620 million.

tessat

Oh 2 different calculations first 26 & 0-9
Second 18 & 0-9

TheChizler

tessat wrote: »

Oh 2 different calculations first 26 & 0-9
Second 18 & 0-9

You're going to have to explain a bit more what exactly you want.

tessat

I'm sorry, I'm trying to work out the difference in available combinations of 6 if using the Irish alphabet versus the English alphabet. So 26 characters in the English alphabet with 0-9 numbers is the first calculation.
The second calculation is 18 characters in the Irish alphabet with 0-9

Does that make sense?

macnug

Would it not be 36 to the power of 6 for the first and 28 to the power of 6 for the second???? Its been a while since of done looked at probability so I'm probably wrong.

Digital Solitude

36x35x34x33x32x31= 1,402,410,240
Almost 1.5 billion

28x27x26x25x24x23= 271,252,800
Less than 300 Million

There are over 5 times as many using the English alphabet. Adding fadas to the Irish one would reduce the deficit somewhat.

Is this correct?

EDIT* Macnug has it right.

Over 2 Billion in English, 2,176,782,336
481,890,304 in Irish.

My first method assumes no characters are repeated

TheChizler

tessat wrote: »

I'm sorry, I'm trying to work out the difference in available combinations of 6 if using the Irish alphabet versus the English alphabet. So 26 characters in the English alphabet with 0-9 numbers is the first calculation.
The second calculation is 18 characters in the Irish alphabet with 0-9

Does that make sense?

Ah I see, as macnug says above so, 36^6 versus 28^6.

ConM96

Is there a specific amount of letters and numbers needed in each combination? I.e does the combination have to consist of one number and 5 letters?

TheChizler

Digital Solitude wrote: »

36x35x34x33x32x31= 1,402,410,240
Almost 1.5 billion

28x27x26x25x24x23= 271,252,800
Less than 300 Million

There are over 5 times as many using the English alphabet. Adding fadas to the Irish one would reduce the deficit somewhat.

Is this correct?

EDIT* Macnug has it right.

Over 2 Billion in English, 2,176,782,336
481,890,304 in Irish.

My first method assumes no characters are repeated

Only if characters can't be reused. I don't think this is a restriction?

Edit: You got the edit in just before I pressed reply!

Digital Solitude

TheChizler wrote: »

Only if characters can't be reused. I don't think this is a restriction?

I'v edited to allow for repeated characters

Aineoil

The first one: a-z + 0-9 = 36 digits altogether. So...

36*35*34*33*32*31/(6*5*4*3*2*1) = 6*7*17*11*8*31 = 1,947,792

Is that right?

draiochtanois

This post has been deleted.

tessat

Not case sensitive
Sorry for the delay coming back, thanks for replying