Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Leaving Cert Paper Q. - Complex Numbers

  • 03-06-2015 6:41pm
    #1
    Registered Users, Registered Users 2 Posts: 490 ✭✭


    Hey,

    My brother is studying for maths on friday. He's having an issue with question number 15 in the pic (complex numbers) - he's getting a bit worried about his method for solving these now. Anybody familiar with these. These bring back terrible memories for me :(


    IMG_20150603_191916.jpg


    Help appreciated :)


Comments

  • Registered Users, Registered Users 2 Posts: 25 YouKnowNothing


    I have the answer here, but I would be terrible at explaining it, enlighten me as to how I can post a photo from my phone please?


  • Registered Users, Registered Users 2 Posts: 490 ✭✭td2008


    cheers - I've private messaged my email, if you want to post it here you can send the photo to your email, download the photo from your email to pc, go to postimage.org , upload the photo and then post the link to the thread


  • Registered Users, Registered Users 2 Posts: 5,637 ✭✭✭TheBody


    There are loads of ways to do it but I'd probably proceed as follows.

    Begin with the polar form and convert to the form [latex]x+iy[/latex]:

    [latex]z=10\sqrt{2}(\cos(\frac{\pi}{4})+i \sin(\frac{\pi}{4}))=10+10i[/latex].

    Next, we can now say that:

    [latex](1+3i)(a+bi)=10+10i[/latex]. Dividing both sides by [latex](1+3i) [/latex] we get:

    [latex](a+bi)=\frac{10+10i}{1+3i}[/latex].

    Al that remains is to do the division on the right and then read off the values of a and b. I'll leave that job up to you!

    Good luck!


  • Registered Users, Registered Users 2 Posts: 490 ✭✭td2008


    Thanks for the help guys - this has helped him out.


  • Registered Users, Registered Users 2 Posts: 5,637 ✭✭✭TheBody


    No problem. Glad to help!


  • Advertisement
Advertisement