Maths Ex Help

2Fast2C

Could someone please tell me how to work out this qs.

I cannot post attatchments but its on pg 50 qs7 all and 9 part 3 text and tests 7

is mise spartacus

7
i) x=-2,1,3
ii) x=1.4 or x=2.8
iii) x³-2x²-5x=0 -> x²-2x-5x+6=0+6=6
Y=6 x=-1.5 or x=0
No: because a horizontal line will cut the graph at more than one point
Surjective: any horizontal line will cut the graph at least once


9 iii) limx³-64 ÷x²-16 = x²+4x+16÷x+4
= (4)²+4(4)+16÷4+4 = 48÷8= 6

2Fast2C

is mise spartacus wrote: »

7
i) x=-2,1,3
ii) x=1.4 or x=2.8
iii) x³-2x²-5x=0 -> x²-2x-5x+6=0+6=6
Y=6 x=-1.5 or x=0
No: because a horizontal line will cut the graph at more than one point
Surjective: any horizontal line will cut the graph at least once


9 iii) limx³-64 ÷x²-16 = x²+4x+16÷x+4
= (4)²+4(4)+16÷4+4 = 48÷8= 6

Hi, thank you so much for the help, but can you tell me how you got the answers for part (i) and (ii) in Q7

2Fast2C

BUMP

is mise spartacus

For i) If you look at the graph and you will see 6 black dots. The black dots at 0 on the x axis are -2, 1 and 3. This is the answer because f(x)=0

For ii) Again look at the graph, this time on the Y axis. The second line from o says -4, above this at the next line, draw a horizontal line. This will be your -2. Where that line touches off the red line place line up touching the x axis. This will roughly show the answer as 1.4 and 2.8

I hope my explanation isn't too complicated

2Fast2C

is mise spartacus wrote: »

For i) If you look at the graph and you will see 6 black dots. The black dots at 0 on the x axis are -2, 1 and 3. This is the answer because f(x)=0

For ii) Again look at the graph, this time on the Y axis. The second line from o says -4, above this at the next line, draw a horizontal line. This will be your -2. Where that line touches off the red line place line up touching the x axis. This will roughly show the answer as 1.4 and 2.8

I hope my explanation isn't too complicated [/QUOTE
GOT IT THANKS A MILL !!