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Questions help please

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  • 05-03-2015 11:43pm
    #1
    Registered Users Posts: 350 ✭✭


    Hi Folks,
    Really struggling would really appreciate if anyone can help with these please.

    Q1: An X-ray diffraction analysis on a substance, with a cubic structure, gives an inter-planar
    spacing (d) of 0.12nm and a lattice parameter (a) of 0.60nm. What is the plane?

    Q2: Nickel has FCC crystal structure. If the angle of diffraction for the (220) set of planes occurs
    at 16.57 degrees (first order) when monochromatic radiation with a wave length of 0.0711nm
    is used; find the inter-planar spacing and the atomic radius.

    q3: Calculate the number of vacancies in Nickel (per cubic meter) at 1050oC, 1250oC and
    1450oC. The energy of formation of a vacancy is 1.4eV. You may assume density remains
    constant with temperature.


    Q4: What is the composition, in atomic percent, of an alloy that contains 50g Cu and 50g Ni.


    Q5. Determine the carburising time necessary to achieve a carbon concentration of 0.5 wt.% at a
    position 3 mm into an iron-carbon alloy that initially contains 0.06 wt.% carbon. The surface
    concentration is to be maintained at 0.85 wt.% carbon, and the treatment is to be conducted at
    1,000°C.
    For C in γ-iron at 1,000°C, the pre-exponential coefficient is given by 2.3x10-5 m
    2
    /s, and the
    activation energy is 148 kJ/mol.

    Thanks in advance.
    Maniac


Comments

  • Registered Users Posts: 6,854 ✭✭✭zuutroy


    Can only help with the first two:
    1
    d= a/sqrt(h^2+k^2+l^2)

    so (h^2+k^2+l^2)= (a/d)^2 = 25. The only plane that satisfies this is the (500).

    _______
    2
    lambda = 2 d sin(theta)
    so d = lambda/2sin(theta)
    When you have 'd' you can solve for 'a' using the equation in Q1.

    For an FCC crystal there are 4 atomic radii across any face, which has a length of (sqrt2)*lattice constant

    so a= 4r/sqrt(2)


  • Registered Users Posts: 350 ✭✭maniac2003


    zuutroy wrote: »
    Can only help with the first two:
    1
    d= a/sqrt(h^2+k^2+l^2)

    so (h^2+k^2+l^2)= (a/d)^2 = 25. The only plane that satisfies this is the (500).

    _______
    2
    lambda = 2 d sin(theta)
    so d = lambda/2sin(theta)
    When you have 'd' you can solve for 'a' using the equation in Q1.

    For an FCC crystal there are 4 atomic radii across any face, which has a length of (sqrt2)*lattice constant

    so a= 4r/sqrt(2)
    thank you so much really big help you've no idea


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