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3L^1/2 x 100 ^1.2

  • 04-11-2014 8:50pm
    #1
    tyga
    Banned (with Prison Access) Posts: 30 ✭


    How does this equal 30L ^1/2?

    Please help


Comments

  • #2
    dlouth15
    Registered Users, Registered Users 2 Posts: 1,169 ✭✭✭dlouth15


    Typo perhaps? I get different numbers when I calculate those out.


  • #3
    Turtwig
    Registered Users, Registered Users 2 Posts: 26,578 ✭✭✭✭Turtwig


    Interpreted it as:
    [latex] 3L^{\frac{1}{2}} * 100^{\frac{1}{2}}[/latex]

    (Assumed the 1.2 is a typo for 1/2)

    Which is basically [latex] 3L^{\frac{1}{2}} * 10[/latex]


  • #4
    tyga
    Banned (with Prison Access) Posts: 30 ✭tyga


    You are correct, typo but my maths intuition is basically zero. Why does the 100 just casually become 10? What happened to the 1/2 power? Does it have something to do with 10 being the square root? I think I read some rule whereby a number to the 1/2 power you square it. But why not do same for the 3^1/2?


  • #5
    tyga
    Banned (with Prison Access) Posts: 30 ✭tyga


    You are correct, typo but my maths intuition is basically zero. Why does the 100 just casually become 10? What happened to the 1/2 power? Does it have something to do with 10 being the square root? I think I read some rule whereby a number to the 1/2 power you square it. But why not do same for the 3^1/2? I'm gana take a leap and say because its a variable?


  • #6
    duffman85
    Registered Users, Registered Users 2 Posts: 339 ✭✭duffman85


    The square root of a number is the same as that number to the power of a half.

    For example: √16 is 4 = 16^0.5

    (16^0.5) *(16^0.5)=16^1

    Similarly x^1/3 is the cubic root.


    For the 3L^1/2 only the L is to the power of a half.

    If it was (3L)^1/2 then you would calculate the square root of 3.


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  • #7
    Turtwig
    Registered Users, Registered Users 2 Posts: 26,578 ✭✭✭✭Turtwig


    Anything to the power of a half is the square root of that number.
    [latex] \sqrt{x} = x^{\frac{1}{2}} [/latex]
    So.
    [latex] \sqrt{100} = 100^{\frac{1}{2}} = 10 [/latex]

    Btw, the answer is very different if its [latex] (3l)^{\frac{1}{2}} [/latex] instead of [latex] 3*(l^{\frac{1}{2}}) [/latex]

    As there was no parenthesis () you assume it's 3 multiplied by L raised to the half power. Be aware of that assumption!

    If there was a parenthesis enclosing both e.g (3l) you'd do exactly what they tell you. Multiply 3 times L first then raise it to whatever power. Bear in mind, without explicit parenthesis or clear structuring all of this is interpretation so be wary that others may follow an different convention. Somebody somewhere may assume 3L^1/2 means (3l)^1/2.


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